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kramer
2 years ago
8

Please help me if yk tha answer :))

Mathematics
1 answer:
Basile [38]2 years ago
3 0

Answer:

cosθ = sinθ/tanθ

Step-by-step explanation:

tanθ = sinθ/cosθ (Given)

cosθ(tanθ) = sinθ (Mulitplied cosθ on both sides)

cosθ = sinθ/tanθ (Divided tanθ on both sides)

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How simplify -8/3 devided by -2/6
Alenkasestr [34]

Answer:

the answer is 8

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
-8x - 10y = 24 <br>6x + 5y = 2<br>​
iris [78.8K]

-8x - 10y = 24

6x + 5y = 2

-8x - 10y = 24

12x + 10y = 4

4x = 28

x = 7

6(7) + 5y = 2

42 + 5y = 2

5y = -40

y = -8

3 0
2 years ago
Read 2 more answers
A rock climber climbs at a rate of 720 feet per hour. Write and solve an equation to find the number of minutes m it takes for t
Lorico [155]

Answer:

The equation is <em>y</em>=12<em>x</em>. It takes 24 minutes for the rock climber to get to 288 feet.

Step-by-step explanation:

Since we know there are 60 minutes in an hour, we can divide 720 by 60. This gives us 12. Therefore, for every minute, the rock climber gets 12 feet higher. Assuming <em>y </em>is the height in feet, and <em>x</em> is the time in minutes, we can create the equation <em>y</em>=12<em>x</em>. Now, to find how long it takes to get to 288 feet, we will substitute y with 288.

288=12<em>x</em>

288/12 = 12x/12

24 = x

Now, we have time in minutes that it takes to get to 288 feet.

Hope this helps!

7 0
2 years ago
which inequality represents all values for x for which the quotient below is defined? square root of 8x squared divided by the s
Strike441 [17]
The answer is D, x > 0
3 0
2 years ago
Calcula la altura de un cono se 235.62cm³ de volumen si el radio de la base mide 5cm​
Ber [7]

Answer:

Datos: r= 24cm. g= 74 cm. ...

- La altura h.

- La generatriz.

- el radio. Que entre ellos forman un triangulo rectángulo siendo la generatriz la hipotenusa y el radio la base, entonces: ...

g²=r²+h² despejando la altura h se tiene que:

h=√g²-r² h= √ (74cm)² - (24 cm)²

es. un paso para que. puedas resolver

6 0
2 years ago
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