Robert Hooke observed the thin slice of cork cells present in the plant cells. In 1665, Robert Hooke referred these empty tiny box-like cavities as cork cells.
<h3>What is Robert Hooke's Observation?</h3>
In 1665, Robert Hooke used a microscope to examine a tiny box-like empty cavities which are referred to as cork cells. He observed that the cork was made up of tiny units that looked like a honeycomb. He referred to them as cells, and he was the first to find a dead cell. This observation has a major contribution in the cell theory.
Hooke published his results under the title Micrographia, about his microscopic observations on several plant tissues. He is remembered as the coiner of the word “cell,” referring to the cavities he observed in thin slices of cork. The cork cells protect the tree from bacterial or fungal infection. It prevents water loss through the bark.
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Answer:
I believe it is Hubble's law but I could be wrong
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Answer/ Explanation:
The original DNA sequence has a point mutation changing a G to a T. The resulting mRNA produced is always complementary to the DNA from which it is synthesised, so the original mRNA sequence has a T, whereas the mutated mRNA has a U. The tRNA is complementary to the mRNA, so the original has a G, and the mutated has a T.
<h3>Original DNA</h3>
GTTGGCGAATGAACGGAGGCTGACGTCTAAGCCTAGAAAAATTGG
RNA
CAACCGCUUACUUGCCUCCGACUGCAGAUUCGGAUCUUUUUAACC
tRNA
GUUGGCGAAUGAACGGAGGCUGACGUCUAAGCCUAGAAAAAUUGG
<h3>_______________________________________________</h3><h3>Mutated DNA</h3>
GTTGGCGAATGAACTGAGGCTGACGTCTAAGCCTAGAAAAATTGG
RNA
CAACCGCUUACUUGUCUCCGACUGCAGAUUCGGAUCUUUUUAACC
tRNA
GUUGGCGAAUGAACTGAGGCUGACGUCUAAGCCUAGAAAAAUUGG
This is a point mutation called a substitution. This does not affect the entire sequence of the protein, because the mutation is "in frame" meaning the mRNA sequence is still read in the same way by the protein producing machinery. However, it does change the 5th codon from UGC to UGU. If we look up the genetic code, we can see that both of these codons code for cysteine, so there will be no change in the amino acid sequence of the protein
Answer:

Explanation:
We are asked to find the energy given mass, specific heat, and change in temperature. Therefore, we must use this formula;

The mass is 15 grams and the specific heat is 0.129 J/(g×°C). Let's calculate the change in temperature.
- ΔT= final temperature - initial temperature
- ΔT= 85 °C- 22°C = 63°C
Now we know all the values:

Substitue the values into the formula.

Multiply the first numbers together. The grams will cancel.

Multiply again, this time the degrees Celsius cancels.

<u>121.905 Joules</u> are required.