Answer:
a) 198
Explanation:
just did the usatestprep
A) 198
Solution:
frequency of aa = q2 = 1/10,000 = 0.0001, q = 0.01
number of aa = 0.0001 x 10,000 = 1 individual
p + q = 1, p = 0.99
frequency of AA = p2 = 0.9801
number of AA = 0.9801 x 10,000 = 9,801 individuals
Aa = 2pq = 2 x 0.9801 x 0.01 = 0.0198 or 198 individuals
A aerobic is the answer
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