Answer:
The Probability that the spinner landed on the colors blue and green in any order = 2/9
Step-by-step explanation:
Given - Azul spun a tri-color spinner twice.
To find - What is the probability that the spinner landed on the colors blue and green in any order?
Solution -
Given that,
A tri-color spinner spun twice
So,
The Sample Space, S = {BB, BG, BY, GB, GG, GY, YB, YG, YY}
⇒n(S) = 9
Now,
Let A be an event that the spinner landed on the colors blue and green
So,
A = {BG, GB}
⇒n(A) = 2
Now,
Probability that the spinner landed on the colors blue and green in any order = n(A) ÷ n(S)
= 2 ÷ 9
∴ we get
The Probability that the spinner landed on the colors blue and green in any order = 2/9
If sinα=1/4 and it is in q2 it means that the x coordinate is negative.
The triangle has a height of one and a hypotenuse of 4 so:
x=-√(4^2-1)
x=-√15
so tanα=-1/√15
tanα=-√(1/15)
tanα≈ -0.258
It’s a expression of a rate in a quantity of one.
9514 1404 393
Answer:
graphs left to right have a=1, a=0.25, a=-1
Step-by-step explanation:
A negative value of 'a' makes the parabola open downward, so the rightmost graph goes with a=-1.
A value of 'a' less than 1 flattens the graph, so the middle graph goes with a=0.25.
A value of 1 gives a standard open-upward parabola, corresponding to the leftmost graph.
<span><span>ΔX =-21
</span><span>
ΔY =<span>25
(-21,25)
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