Answer:
correct option is C) 2.8
Step-by-step explanation:
given data
string vibrates form = 8 loops
in water loop formed = 10 loops
solution
we consider mass of stone = m
string length = l
frequency of tuning = f
volume = v
density of stone =
case (1)
when 8 loop form with 2 adjacent node is
so here
..............1

and we know velocity is express as
velocity = frequency × wavelength .....................2
= f ×
here tension = mg
so
= f ×
..........................3
and
case (2)
when 8 loop form with 2 adjacent node is
..............4

when block is immersed
equilibrium eq will be
Tenion + force of buoyancy = mg
T + v ×
× g = mg
and
T = v ×
- v ×
× g
from equation 2
f ×
= f ×
.......................5
now we divide eq 5 by the eq 3

solve irt we get

so
relative density 
relative density = 2.78 ≈ 2.8
so correct option is C) 2.8
Answer:
y = 2x + 10
Step-by-step explanation:
Find the slope:
12 - 2 / 1 - (-4)
10 / 5 = 2
Write in point-slope form:
y - 12 = 2(x - 1)
rearrange:
y - 12 = 2x - 2
y = 2x + 10
2/5 = ?/10 = 0.4
2*(2/5) = (2*2)/(2*5) = 4/10
? = 4
Hey there!
The answer to your question is Crew A
We can find this by first finding the unit rate, or acres per hour. We can divide the amount of acres by the amount of hours.
Crew A : 6/7.5 = 0.8 acres per hour
Crew B : 4.5/6 = 0.75 acres per hour
With the data above, we can see that Crew A is faster.
Hope it helps and have an amazing day! Remember, You've got this!
Answer:
Length = 45.37 in
Width = 30.56 in
Step-by-step explanation:
Let the width of the picture be 'w' inches.
Given:
Perimeter of the picture is, 
Length is 15.75 inches shorter than twice the width. So, length is:

Now, we know that the perimeter of a rectangular shape is given as the sum of all of its side. So, the picture is also of rectangular shape and hence the perimeter is given as:

Plug in the values of 'l' and 'P' and solve for 'w'. This gives,

Therefore, the width of the rectangular picture is 30.56 inches.
Length of the picture is, 
So, length of the picture is 45.37 inches and width is 30.56 inches.