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AnnyKZ [126]
3 years ago
7

Two boxes on a horizontal plane with coefficient of friction µ are connected by a massless string. The left-hand box has mass m

and the right-hand box has mass 2m. A force F is applied to the right-hand mass at an angle θ with respect to the horizontal so that they move to the right at constant acceleration. What is the magnitude of the tensi
Physics
1 answer:
pochemuha3 years ago
5 0

Answer:

T = (3μmg - Fcosθ)/2

Explanation:

Since the boxes move to the right, the net force on box of mass 2m is

Fcosθ - 2μmg + T = ma (1)where Fcosθ = horizontal component of applied force, 2μmg = frictional force and T = tension in string and a = acceleration of box

The net force on the box with mass m is

μmg - T = ma (2) where μmg = frictional force, T = tension and a = acceleration of boxes.

Equating (1) and (2) we have

Fcosθ - 2μmg + T = μmg - T

collecting like terms

Fcosθ - 2μmg - μmg = -T - T

Fcosθ - 3μmg = -2T

(3μmg - Fcosθ)/2 = T

T = (3μmg - Fcosθ)/2

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You have a mass of 55kg and are riding your frictionless skateboard, which has a mass of 5kg, in a straight line at a speed of 4
Rzqust [24]

Given

m1(mass of the first object): 55 Kg

m2 (mass of the second object): 55 Kg

v1 (velocity of the first object): 4.5 m/s

v2 (velocity of the second object): ?

m3(mass of the object dropped): 2.5 Kg

The law of conservation of momentum states that when two bodies collide with each other, the momentum of the two bodies before the collision is equal to the momentum after the collision. This can be mathemetaically represented as below:

Pa= Pb

Where Pa is the momentum before collision and Pb is the momentum after collision.

Now applying this law for the above problem we get

Momentum before collision= momentum after collision.

Momentum before collision = (m1+m2) x v1 =(55+5)x 4.5 = 270 Kgm/s

Momentum after collision = (m1+m2+m3) x v2 =(55+5+2.5) x v2

Now we know that Momentum before collision= momentum after collision.

Hence we get

270 = 62.5 v2

v2 = 4.32 m/s




7 0
3 years ago
Which safety procedure should you follow after breaking a mercury thermometer?
agasfer [191]
B. move away from the mercury and notify the teacher :)

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Pouring the mercury in the sink would likely be logged in the plumbing. and pickingthings up with the napkin may cause contamination and cuts from the glass.
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3 years ago
All are examples of speed except ______
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4 years ago
A research-level Van de Graaff generator has a 2.15 m diameter metal sphere with a charge of 5.05 mC on it. What is the potentia
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Answer:

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Explanation:

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r = radius of the metal sphere

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r = 1.075 m

Q = charge on sphere = 5.05 mC = 5.05 x 10⁻³ C

Potential near the surface is given as

V = \frac{kQ}{r}

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4 years ago
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