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2 years ago

Power can be defined as

Physics

2 answers:

Zepler [3.9K]2 years ago

8 0

Answer:

the correct answer is B how much work can be done in a given time

Explanation:

maria [59]2 years ago

4 0

I think it’s D sorry If I’m wrong

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Consider a small child sliding down two differently shaped slides that have the same coefficient of kinetic friction. How must t

timama [110]

Answer:

Having a bigger angle above the horizontal

Explanation:

Applying the energy conservation theorem:

$K_1+U_1+W_{ext}=K_2+U_2$

The kinetic energy is reduced because of the work done by the friction force.

The friction force is given by:

$F_f=F_N*\µ$

so the friction force depends on the Normal force, because the slide has an angle the normal force is given by:

$F_N=m.g*cos(\theta)$

So when the angle of the slide is bigger, the friction force decreases, for example:

for 45 degrees:

$F_N=m.g*cos(45)\\F_N=0.70(m.g)\\$

for 75 degrees:

$F_N=m.g*cos(75)\\F_N=0.26(m.g)\\$

as you can see if the angle is bigger above the horizontal, the friction force is reduced and so the work done by that force. We didn't have to change the height of the slide, so the potential gravitational energy remains the same.

6 0

3 years ago

How many earths could fit inside jupiter

Snezhnost [94]

1,300 or more.

hope this helped :)

8 0

3 years ago

If a 400-mm diameter pipe with a pipe roughness coefficient of 100 flows full of pressurized water with a head loss of 0.4 ft pe

RoseWind [281]

Answer:

Q = 913.9 gpm

Explanation:

The Hazen Williams equation can be written as follows:

$P = \frac{4.52\ Q^{1.85}}{C^{1.85}d^{4.87}}$

where,

P = Friction Loss per foot of pipe = $\frac{0.4}{1000\ ft}$ = 4 x 10⁻⁴

Q = Flow Rate in gallon/min (gpm) = ?

d = pipe diameter in inches = (400 mm)(0.0393701 in/1 mm) = 15.75 in

C = roughness coefficient = 100

Therefore,

$4\ x \ 10^{-4} = \frac{4.52\ Q^{1.85}}{(100)^{1.85}(15.75)^{4.87}}\\\\Q^{1.85} = \frac{4\ x \ 10^{-4}}{1.33\ x\ 10^{-9}} \\\\Q = (300384.75)^\frac{1}{1.85}$

5 0

3 years ago

PLS HELP!!! WILL GIVE BRAINLIEST

grandymaker [24]

Answer:

did you ever get the answer

8 0

2 years ago

Read 2 more answers

Find the density of seawater at a depth where the pressure is 500 atm if the density at the surface is 1100 kg/m^3 . Seawater ha

mixer [17]

The density of seawater at a depth where the pressure is 500 atm is $1124kg/m^3$

Explanation:

The relationship between bulk modulus and pressure is the following:

$B=\rho_0 \frac{\Delta p}{\Delta \rho}$

where

B is the bulk modulus

$\rho_0$ is the density at surface

$\Delta p$ is the variation of pressure

$\Delta \rho$ is the variation of density

In this problem, we have:

$B=2.3\cdot 10^9 N/m^2$ is the bulk modulus

$\rho_0 =1100 kg/m^3$

$\Delta p = p-p_0 = 500 atm - 1 atm = 499 atm = 5.05\cdot 10^7 Pa$ is the change in pressure with respect to the surface (the pressure at the surface is 1 atm)

Therefore, we can find the density of the water where the pressure is 500 atm as follows:

$\rho = \rho_0 + \Delta \rho = \rho_0+\frac{\rho_0 \Delta p}{B}=\rho_0 (1+\frac{\Delta p}{B})=(1100)(1+\frac{5.05\cdot 10^7}{2.3\cdot 10^9})=1124kg/m^3$

Learn more about pressure in a fluid:

brainly.com/question/9805263

#LearnwithBrainly

7 0

3 years ago