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2 years ago

13

Can somebody hack ur account on Brainly bc I feel like I have bc I have answered waaaaaay more questions than shows on my profil

e and idk what happened so fr pls tell me what happened anyone...?

Computers and Technology

1 answer:

QveST [7]2 years ago

4 0

It says you’ve only answered 11, but yeah it you’re account CAN be hacked

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the volume of two similar solids are 1080cm and 1715cm .if the curved surface area of the smaller cone is 840cm .fond the curved

gavmur [86]

Answer:

$A_{big} = 1143.33cm^2$

Explanation:

The given parameters are:

$V_{small} = 1080$

$V_{big} = 1715$

$C_{small} = 840$

Required

Determine the curved surface area of the big cone

The volume of a cone is:

$V = \frac{1}{3}\pi r^2h$

For the big cone:

$V_{big} = \frac{1}{3}\pi R^2H$

Where

R = radius of the big cone and H = height of the big cone

For the small cone:

$V_{small} = \frac{1}{3}\pi r^2h$

Where

r = radius of the small cone and H = height of the small cone

Because both cones are similar, then:

$\frac{H}{h} = \frac{R}{r}$

and

$\frac{V_{big}}{V_{small}} = \frac{\frac{1}{3}\pi R^2H}{\frac{1}{3}\pi r^2h}$

$\frac{V_{big}}{V_{small}} = \frac{R^2H}{r^2h}$

Substitute values for Vbig and Vsmall

$\frac{1715}{1080} = \frac{R^2H}{r^2h}$

Recall that: $\frac{H}{h} = \frac{R}{r}$

So, we have:

$\frac{1715}{1080} = \frac{R^2*R}{r^2*r}$

$\frac{1715}{1080} = \frac{R^3}{r^3}$

Take cube roots of both sides

$\sqrt[3]{\frac{1715}{1080}} = \frac{R}{r}$

Factorize

$\sqrt[3]{\frac{343*5}{216*5}} = \frac{R}{r}$

$\sqrt[3]{\frac{343}{216}} = \frac{R}{r}$

$\frac{7}{6} = \frac{R}{r}$

The curved surface area is calculated as:

$Area = \pi rl$

Where

$l = slant\ height$

For the big cone:

$A_{big} = \pi RL$

For the small cone

$A_{small} = \pi rl$

Because both cones are similar, then:

$\frac{L}{l} = \frac{R}{r}$

and

$\frac{A_{big}}{A_{small}} = \frac{\pi RL}{\pi rl}$

$\frac{A_{big}}{A_{small}} = \frac{RL}{rl}$

This gives:

$\frac{A_{big}}{A_{small}} = \frac{R}{r} * \frac{L}{l}$

Recall that:

$\frac{L}{l} = \frac{R}{r}$

So, we have:

$\frac{A_{big}}{A_{small}} = \frac{R}{r} * \frac{R}{r}$

$\frac{A_{big}}{A_{small}} = (\frac{R}{r})^2$

Make $A_{big}$ the subject

$A_{big} = (\frac{R}{r})^2 * A_{small}$

Substitute values for $\frac{R}{r}$ and $A_{small}$

$A_{big} = (\frac{7}{6})^2 * 840$

$A_{big} = \frac{49}{36} * 840$

$A_{big} = \frac{49* 840}{36}$

$A_{big} = 1143.33cm^2$

<em>Hence, the curved surface area of the big cone is 1143.33cm^2</em>

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3 years ago

Select the best answer for the question. 2. What is the simplest way to permanently get rid of an unwanted file?

Kobotan [32]

To permanetly get rid of an unwanted file, you delete it

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The term generally used to describe storage systems that function at high speeds is:

Alinara [238K]

The term to describe storage systems that function at high speeds is primary memory.

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The average pH of citrus fruits is 2.2, and this value has been stored in the variable avg_citrus_pH . Provide a statement to di

olasank [31]

Answer:

The statement in Python is:

print("The average pH of citrus fruits is ",avg_citrus_pH)

Java

System.out.print("The average pH of citrus fruits is "+avg_citrus_pH);

C++

cout<<"The average pH of citrus fruits is "<<avg_citrus_pH;

Explanation:

The programming language is not stated; so, I answered the question in 3 languages (Python, Java and C++)

Assume that avg_citrus_pH has been declared and initialized; all you need to do is invoke a print statement and then append the variable

In Python, use print()

In c++, use cout<<

In Java, use System.out.print()

So, the statements are:

Python:

print("The average pH of citrus fruits is ",avg_citrus_pH)

Java

System.out.print("The average pH of citrus fruits is "+avg_citrus_pH);

C++

cout<<"The average pH of citrus fruits is "<<avg_citrus_pH;

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2 years ago

A user deletes a message from a mailbox while on a desktop. What happens to the email message on the user's synchronized devices

gulaghasi [49]

Answer:

Explanation:

Depends on the configuration of the email because there are two protocols POP and IMAP, the most recent protocol is IMAP, we can delete an email and this It moves to a To be Deleted folder, this happens because the email is stored in the server, but with the protocol POP the email is stored in the server and downloaded to the application, if you delete an email, this is deleted in all devices.

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3 years ago

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