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maksim [4K]
2 years ago
13

Do the substances that are reactants in a chemical reaction remain the same after the reaction is complete?

Chemistry
1 answer:
pishuonlain [190]2 years ago
4 0
The first answer is nine you are currently correct
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7. NH2CO2NH4(s) when heated to 450 K undergoes the following reaction to produce a system which reaches equilibrium: NH2CO2NH4(s
Taya2010 [7]

Answer:

Value of equilibrium constant is 0.0888

Explanation:

Both NH_{3} and CO_{2} are gaseous. Hence equilibrium constant depends upon partial pressures of NH_{3} and CO_{2}.

Initially no NH_{3} and CO_{2} were present.

Hence mole fraction of NH_{3} and CO_{2} at equilibrium can be calculated from coefficient of NH_{3} and CO_{2} in balanced equation.

Mole fraction of NH_{3} = (number of moles of NH_{3})/(total number of moles of NH_{3} and CO_{2}) = \frac{2moles}{(2+1)moles}=\frac{2}{3}

Mole fraction of CO_{2} = (number of moles of CO_{2})/(total number of moles of NH_{3} and CO_{2}) = \frac{1moles}{(2+1)moles}=\frac{1}{3}

Let's assume both CO_{2} and NH_{3} behaves ideally.

Therefore partial pressure of NH_{3}, P_{NH_{3}}= x_{NH_{3}}.P_{total} and P_{CO_{2}}= x_{CO_{2}}.P_{total}

Where x represents mole fraction

So, P_{NH_{3}}=\frac{2}{3}\times 0.843atm=0.562atm

P_{CO_{2}}=\frac{1}{3}\times 0.843atm=0.281atm

So, K_{p}=P_{NH_{3}}^{2}.P_{CO_{2}}=(0.562)^{2}\times 0.281=0.0888

4 0
3 years ago
A student was given a piece of metal with a mass of 85.0 g. She placed it
Anastasy [175]

Answer:

22mL

Explanation:

6 0
3 years ago
Minerals in igneous rocks that form from lava are large because lava cools slowly.
natulia [17]

Answer:

They is called heat.

Explanation:

8 0
3 years ago
Notice that " s o 4 " appears in two different places in this chemical equation. s o 2− 4 is a polyatomic ion called "sulfate."
Amanda [17]
A "3" should but put in front of
<span>"cas o 4 "</span>
6 0
3 years ago
Which statement is true? 1. The electronegativity of an atom depends only on the value of the ionization energy of the atom. 2.
lisov135 [29]

Answer:

5. Atoms with high ionization energies and high electron affinities have low electronegativities.

Explanation:

Ionization energy is the minimum amount of energy which is required to knock out the loosely bound valence electron from the isolated gaseous atom.

Electron affinity is the amount of energy released when an isolated gaseous atom accepts electron to form the corresponding anion.

Electronegativity is the tendency of an atom in a bond pair to attract the shared pair of electron towards itself.

Low ionization energies as well as low electron affinities mean the atom has low effective nuclear charge, which results in the less attraction of the valence electrons by the atom and thus, low electronegativity.

6 0
3 years ago
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