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3 years ago

What is the name of bird W?

Chemistry

1 answer:

Bingel [31]3 years ago

4 0

Answer:

woodpecker it's easy lil lol

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A student places a small amount of water in a glass dish and then carefully places a small paperclip on the surface of the water

rosijanka [135]

Include:
- Adding cleanser makes the paperclip fall through the water to the base of the dish.
- Soap is a surfactant.
- Surfactants lessen the surface pressure of a fluid.
- The surface strain of water is the thing that upheld the paper cut.

3 0

3 years ago

Read 2 more answers

Volume of HCl used 25.0mL 4 l

borishaifa [10]

Answer:

1.0 M

Explanation:

Reaction equation;

KOH(aq) + HCl(aq) -----> KCl(aq) + H2O(l)

Concentration of acid CA = ?

Concentration of base CB = 1.0 M

Volume of base VB = 25.60 - 0.50 = 25.1 ml

Volume of acid VB = 25.0 ml

Number of moles of acid NA = 1

Number of moles of base NB =2

CAVA/CBVB =NA/NB

CAVANB = CBVBNA

CA = CBVBNA/VANB

CA = 1 * 25.1 * 1/25.0 *1

CA = 1.0 M

8 0

3 years ago

A metal melts at 450 degrees celsius. Is this property of the metal classified as chemical or physical?

Romashka-Z-Leto [24]

It's a physical property because it doesn't change the element of the metal.
does this make sense?

8 0

3 years ago

If you are traveling at 60mi/hr, how many meters per second is that equivalent to?

lesya [120]

Answer:

26.8224 Meters per Second.

5 0

2 years ago

Assume that the test tube shown started out having 10.00 g of mercury(II) oxide. After heating the test tube briefly, you find 1

anyanavicka [17]

This problem is providing information about the initial mass of mercury (II) oxide (10.00 g) which is able to produce liquid mercury (8.00 g) and gaseous oxygen and asks for the resulting mass of the latter, which turns out to be 0.65 g after doing the corresponding calculations.

Initially, it is given a mass of 10.00 g of the oxide and 1.35 g are left which means that the following mass is consumed:

$m_{HgO}^{consumed}=10.00g-1.35 g=8.65 g$

Now, since 8.00 grams of liquid mercury are collected, it is possible to calculate the grams of oxygen that were produced, by considering the law of conservation of mass, which states that the mass of the products equal that of the reactants as it is nor destroyed nor created. In such a way, the mass of oxygen turns out to be:

$m_{O_2}=8.65g-8.00g=0.65g$

Learn more:

3 0

2 years ago