The answer is 2*(l+b) = 2*(2.3)=4.6
Answer:
Please see attached image for the graph
Step-by-step explanation:
To graph the elevation versus time, we start by plotting the first point at time zero (when the climb begins) when Zane is 20 meters below the edge (-20 meters). This corresponds to the point (0, -20).
One second later (1 in the horizontal axis), Zane has moved up 4 meters, now reaching -16 meters. This is the point (1, -16) on the graph.
One second later at time 2 seconds, he is another 4 meters up which corresponds to the point (2, -12) on the graph.
you can go on like this plotting more points on the graph.
Please see the attached image that illustrates this and shows the appropriate line that represents Zane's position versus time (pictured in red)
<span><span><span><span>The word "slope" may also be referred to as "gradient", "incline" or "pitch", and be expressed as:
A special circumstance exists when working with straight lines (linear functions), in that the "average rate of change" (the slope) is </span>constant.<span> No matter where you check the slope on a straight line, you will get the same answer.</span> </span></span><span><span><span> Non-Linear Functions:</span>When working with <span>non-linear functions, </span>the "average rate of change" is not constant.
The process of computing the "average rate of change", however, remains the same as was used with straight lines: two points are chosen, and is computed.<span>FYI: </span>You will learn in later courses that the "average rate of change" in non-linear functions is actually the slope of the secant line passing through the two chosen points. A secant line cuts a graph in two points.</span></span></span>
When you find the "average rate of change" you are finding the rate at which (how fast) the function's y-values (output) are changing as compared to the function's x-values (input).
When working with functions (of all types), the "average rate of change" is expressed using<span>function notation.</span>
A
You want to do this when your heart is at its most normal level