Answer:
13
Explanation:
13.0120481928 it is the distance
F = G m1*m2 / r^2 => [G] = [F]*[r]^2 /([m1]*[m2]) = N * m^2 / kg^2
That is one answer.
Also, you can use the fact that N = kg*m/s^2
[G] = kg * m / s^2 * m^2 / kg^2 = m^3 /(s^2 * kg)
Answer:
magnitude = 304.14 km/h
direction:
West of North
Explanation:
The final plane's vector velocity will be the result of the vector addition of one pointing North of length 300 km/h, another one pointing West of length 50 km/h.
To find the magnitude of the final velocity vector (speed) we need to apply the Pythagorean theorem in a right angle triangle with sides: 300 and 50, and find its hypotenuse:
km/h
The actual direction of the plane is calculated using trigonometry, in particular with the arctan function, since the tangent of the angle can be written as:

So the resultant velocity vector of the plane has magnitude = 304.14 km/h,
and it points
West of the North direction.
Think it would be c, 5.1 g
Question: What was his initial velocity?
Answer: 3.62 m/s