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Alchen [17]
2 years ago
13

Pls help i will literally venmo you im not even kidding

Physics
1 answer:
Marizza181 [45]2 years ago
6 0

For Question 6:

The formula for momentum to express the conservation of momentum of two objects in a collision is:

m1 • v1 + m2 • v2 = m1 • v1' + m2 • v2'

m1 and m2 are the masses so

63v1 + 55v2 = 63v1' + 55v2'

v1 and v2 represent the velocities before the collision, so

(63)(0) + (55)(0) = 63v1' + 55v2'

v1' and v2' represent the velocities after the collision, so

(63)(0) + (55)(0) = (63)(3.3) + (55)v2' <-- We're looking for v2'

0 + 0 = 207.9 + 55v2'

-207.9 = 55v2'

-3.78 m/s = v2'

The answer is negative because the 55kg skater is moving to the left.

For Question 7:

The formula for momentum is p = m • v

so we have:

3.9 = .15v

26 m/s = v

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Note :

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Give reason for the following:
Zigmanuir [339]

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HOPE IT HELPS...

5 0
2 years ago
Una niña está empujando un baúl. El PESO del baúl es de 230 N y el roce es de 50 N, la niña sólo logra ejercer una fuerza de 30
Gre4nikov [31]

Answer:

Su padre necesita aplicar una fuerza de 20 newtons en la misma dirección que la fuerza aplicada por su hija.

Explanation:

Asúmase que el baúl se mueve en una superficie horizontal. La fuerza de rozamiento dada por el problema es la fuerza de rozamiento estático máximo, se requiere una fuerza externa antiparalela a la fuerza de rozamiento estático máximo para que el baúl se empiece a mover. La ecuación de equilibrio de fuerzas horizontales sobre el baúl es:

\Sigma F = P - f = 0

Donde:

P - Fuerza externa aplicada sobre el baúl, medida en newtons.

f - Fuerza de rozamiento estático máximo, medida en newtons.

Se despeja la fuerza externa:

P = f

Si f = 50\,N, entonces:

P = 50\,N

Si la niña solo logra ejercer una fuerza de 30 newtons, su padre necesita aplicar una fuerza de 20 newtons paralela a aquella fuerza.

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