Answer:
volume of air breath = 495.75 mL per min
Explanation:
given data
oxygen required = 2.4 × 10² mL / Min = 240 mL
inhaled air = 20 %
exhaled air = 16 %
to find out
volume of air per breath
solution
we know here that breathes 12 time every minute
and we consider here air breath = y per min
we know oxygen remain in body = 20 % - 16 % = 4%
and required 12 time air breath
so air required = 240 / 12 = 19.83 mL
so oxygen breath equation will be
y × 4% = 19.83
y = 19.83 / 0.04
y = 495.75
so volume of air breath = 495.75 mL per min
Displacement is the straight-line distance and direction from start-point to end-point, regardless of the actual path taken.
In this example, that's 10.3 km (rounded) in the direction 14 degrees west of South.
Answer:
counterclockwise
Explanation:
given data
area = 25 cm²
solution
We know that a changing magnetic field induces the current and induced emf is express as
..................................1
and we will get here direction of the induced current in the loop that is express by the Lens law that state that the direction of induces current is such that the magnetic flux due to the induced current opposes the change in magnetic flux due to the change in magnetic field
so when magnetic field decrease and point coming out of the paper.
so induced current in the loop will be counterclockwise
Answer:
its good no need to change anything :))
Answer: 71.7 KJ
Explanation:
The rotational kinetic energy of a rotating body can be written as follows:
Krot = ½ I ω2
Now, any point on the rim of the flywheel, is acted by a centripetal force, according to Newton’s 2nd Law, as follows:
Fc = m. ac
It can be showed that the centripetal acceleration, is related with the angular velocity and the radius, as follows:
ac = ω2 r
We know that this acceleration has a limit value, so , we can take this limit to obtain a maximum value for the angular velocity also.
As the flywheel is a solid disk, the rotational inertia I is just ½ m r2.
Replacing in the expression for the Krot, we have:
Krot= ½ (1/2 mr2.ac/r) = ¼ mr ac = ¼ 67.0 Kg. 1.22 m . 3,510 m/s2 = 71. 7 KJ