Units such as kilograms (about 2.2 pounds)n which are a thousand grams,grams,centigrams (hundredths of grams), and milligrams (thousands of grams).
There is a missing part in the question. Found the complete text on internet:
"<span>What is the largest size vehicle (kg) it can lift if the diameter of the output line is 28.0 cm? "
Solution
The diameter of the piston is 28.0 cm, this means its radius is 14.0 cm (half the diameter), so the area of the piston is
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The maximum pressure of the lift is
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Therefore the maximum force the piston can lift is
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And the size (the mass) of the vehicle is
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The statements that describe a benefit of the scientific method are as follows:
- It gives scientists a standardized way to approach a problem.
- It reduces bias and judgment from personal experiences.
- It gives scientists a common vocabulary for sharing information.
Thus, the correct options are B, C, and D.
<h3>What is the Scientific method?</h3>
The scientific method may be defined as a strategy of research in which a problem is recognized, relevant data is collected, a conjecture is composed of this data, and the assumption is empirically tested to determine the outcome of particular research.
The scientific method never explains or provides an answer to any question immediately because it consists of a scripted format with certain parameters.
The scientific method uses the identical vocabulary for sharing information with one another in particular terminology.
Therefore, it is well described above.
To learn more about the Scientific method, refer to the link:
brainly.com/question/17216882
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Answer: final Displacement = 0 km, total distance covered =7 km
Explanation:
Given the following :
From home to library = 1.3 km East
Library to music store = 0.68km East
Music store to friend's house = 1.1km North
Friend's house to grocery store = 0.42 km North
Displacement is the net change in distance traveled.
Eastward distance :
To = (1.3 + 0.68)km = 1.98km East
Fro = (0.68 + 1.3)km = 1.98 km East
Δ distance = (1.98 - 1.98) = 0
Northward direction:
To = (1.1 + 0.42)km = 1.52km north
Fro = (0.42 + 1.1)km = 1.52km North
Δ distance = (1.98 - 1.98) = 0
Hence final Displacement = 0
Total distance covered = 2 × (1.3 + 0.68 + 1.1 + 0.42) = 2 × 3.5
= 7km
<h2>a) Average velocity in first 4 seconds is 64 ft/s upward</h2><h2>b) Average velocity in second 4 seconds is 63.5 ft/s downward</h2>
Explanation:
a) Given S(t) = 76 + 128t − 16t²
s(0) = 76 + 128 x 0 − 16 x 0² = 76 ft
s(4) = 76 + 128 x 4 − 16 x 4² = 332 ft
Displacement in 4 seconds = 332 - 76 = 256 ft
Time = 4 - 0 = 4 s

Average velocity in first 4 seconds is 64 ft/s upward
a) Given S(t) = 76 + 128t − 16t²
s(4) = 76 + 128 x 4 − 16 x 4² = 332 ft
s(8) = 76 + 128 x 8 − 16 x 8² = 78 ft
Displacement in 4 seconds = 78 - 332 = -254 ft
Time = 4 - 0 = 4 s

Average velocity in second 4 seconds is 63.5 ft/s downward