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ludmilkaskok [199]
3 years ago
10

What would be an advantage of a series circuit? ||

Chemistry
1 answer:
Arte-miy333 [17]3 years ago
8 0

Answer: You can have a loop in a series circuit than a parallel circuit

Explanation: You can have a loop! How is this loop helpful? I don't know, I have no idea how this would be useful. Ah! maybe you can have many things activate sequentially like a lightshow. You can make a series circuit and it will just repeat. You can repeat a lightshow. I don't know what else you can do.

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Im literally failing some classes can some one help me with them
galben [10]

Answer:in can

Explanation:

5 0
3 years ago
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How many moles of CO2 are there in 2.55 x 10<br><br> 18<br><br> molecules of CO2?
cluponka [151]

Answer: There are 4.23\times 10^{-6}moles  of CO_2

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number 6.023\times 10^{23} of particles.

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given molecules}}{\text {Avogadros number}}

\text{Number of moles}=\frac{2.55\times 10^{18}}{6.023\times 10^{23}}=0.423\times 10^{-5}moles

Thus there are 4.23\times 10^{-6}moles  of CO_2

6 0
3 years ago
I need help please will give brainliest but need two people to answer
Leto [7]

Answer:

It is the concept of surface tension that helps the coin to float on the top of the water in the glass. The surface tension acts just opposite to the gravitational force and that is why when any metal placed in the water it will float and come on the surface.

4 0
3 years ago
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You prepare a standard by weighing 10.751 mg of compound X into a 100 mL volumetric flask and making to volume. You further dilu
ArbitrLikvidat [17]

Answer:

0.12693 mg/L

Explanation:

First we <u>calculate the concentration of compound X in the standard prior to dilution</u>:

  • 10.751 mg / 100 mL = 0.10751 mg/mL

Then we <u>calculate the concentration of compound X in the standard after dilution</u>:

  • 0.10751 mg/mL * 5 mL / 25 mL = 0.021502 mg/L

Now we calculate the<u> concentration of compound X in the sample</u>, using the <em>known concentration of standard and the given areas</em>:

  • 2582 * 0.021502 mg/L ÷ 4374 = 0.012693 mg/L

Finally we <u>calculate the concentration of X in the sample prior to dilution</u>:

  • 0.012693 mg/L * 50 mL / 5 mL = 0.12693 mg/L
4 0
3 years ago
Aqueous magnesium chloride is added to aqueous silver nitrate. A white precipitate forms. Write the chemical equation for this r
Butoxors [25]

Answer:

1. Molecular equation

BaCl2(aq) + 2AgNO3(aq) –> 2AgCl(s) + Ba(NO3)2 (aq)

2. Complete Ionic equation

Ba²⁺(aq) + 2Cl¯(aq) + 2Ag⁺(aq) + 2NO3¯ (aq) —> 2AgCl(s) + Ba²⁺(aq) + 2NO3¯(aq)

3. Net ionic equation

Cl¯(aq) + Ag⁺(aq) —> AgCl(s)

Explanation:

4 0
3 years ago
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