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Fynjy0 [20]
2 years ago
6

A 2.75 M solution is diluted to 0.706 M, if the starting volume was 0.833L, what is the new volume?

Chemistry
1 answer:
Nitella [24]2 years ago
8 0

Answer:

3.2447

Explanation:

m1v1 = m2v2

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Ammonia is a main ingredient in fertilizers. The following reaction is used to synthesize ammonia, NH3. How many liters of ammon
PolarNik [594]
According to Balance chemical equation,

                                         N₂  +  3 H₂    →     2 NH₃

1 mole of Nitrogen reacts with 3 moles of Hydrogen to produce 2 mole of Ammonia.
It is known that i mole of any gas at standard temperature and pressure occupies 22.4 L of Volume. So, we can also say,

22.4 L (1 × 22.4) of Nitrogen gas (in question it is taken in excess) reacts with 67.2 L (22.4 × 3) of Hydrogen gas to produce 44.8 L (22.4 × 2) of Ammonia.

Result:
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If 50 g of lead (of specific heat 0.11 kcal/kg ∙ C°) at 100°C is put into 75 g of water (of specific heat 1.0 kcal/kg ∙ C°) at 0
Contact [7]

Answer: The final temperature is 279.8K

Explanation:

heat_{absorbed}=heat_{released}

As we know that,  

Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})

m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]         .................(1)

where,

q = heat absorbed or released

m_1 = mass of lead = 50 g

m_2 = mass of water = 75 g

T_{final} = final temperature = ?

T_1 = temperature of lead = 100^oC=373K

T_2 = temperature of water = 0^oC=273K

c_1 = specific heat of lead = 0.11kcal/kg^0C

c_2 = specific heat of water= 1.0kcal/kg^0C

Now put all the given values in equation (1), we get

50\times 0.11\times (T_{final}-373)=-[75\times 1.0\times (T_{final}-273)]

T_{final}=279.8K

Therefore, the final temperature of the mixture will be 279.8 K.

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<span>hard as in solid at room temp </span>
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Which is the correct empirical formula for C6H1206?
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the correct empirical formula for C6H12O6 is CH2O...

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