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4 years ago

Help me on a and b pls

Chemistry

1 answer:

marusya05 [52]4 years ago

5 0

Answer:

yes, it is increased by atomic mass

Explanation:

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The compound trimethylamine, (CH3)3N, is a weak base when dissolved in water. Write the Kb expression for the weak base equilibr

GREYUIT [131]

Answer:

The $K_b$ expression for the weak base equilibrium is:

$K_b=\frac{[(CH_3)_3NH^+][OH^-]}{[(CH_3)_3N]}$

Explanation:

$(CH_3)_3N(aq)+H_2O(l)\rightlefharpoons (CH_3)_3NH^++OH^-(aq)$

The expression of the equilibrium constant of base $K_c$ can be given as:

$K_c=\frac{[(CH_3)_3NH^+][OH^-]}{[(CH_3)_3N][H_2O]}$

] $K_b=K_c\times [H_2O]=\frac{[(CH_3)_3NH^+][OH^-]}{[(CH_3)_3N]}$

As we know, water is pure solvent, we can put $[H_2O]=1$

$K_b=K_c\times 1=\frac{[(CH_3)_3NH^+][OH^-]}{[(CH_3)_3N]}$

So, the the $K_b$ expression for the weak base equilibrium is:

$K_b=\frac{[(CH_3)_3NH^+][OH^-]}{[(CH_3)_3N]}$

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3 years ago

Describe the process of Filtration in the Nephron

Roman55 [17]

Filtration is the mass movement of water and solutes from plasma to the renatubule that occurs in the renal corpuscle, hope it helps

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3 years ago

E=hv h= 6.62 x 10^-34 m^2 kg/ s

Drupady [299]

v=5.0×10^12Hz

$\\ \sf\longmapsto E=hv$

$\\ \sf\longmapsto E=6.626\times 10^{-34}Js\times 5\times 10^12s^{-1}$

$\\ \sf\longmapsto E=33.13\times 10^{-22}J$

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3 years ago

Pretend you’re rinding the bus to school in a very cold and snowy day. List 3 different phases changes you might see along the w

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Answer:

Everyone wearing warm clothes.

Everyone with their cheeks red.

Everyone eating or drinking hot food

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2 years ago

15.50 g of NH4Cl reacts with an excess of AgNO3. In the reaction 35.50 g AgCl is produced. what is the theoretical yield of AgCl

Shkiper50 [21]

Answer:

41.56 g

Explanation:

Given data:

Mass of NH₄Cl = 15.50 g

Actual yield of AgCl = 35.50 g

Theoretical yield of AgCl = ?

Solution:

Chemical equation:

NH₄Cl + AgNO₃ → AgCl + NH₄NO₃

Number of moles of NH₄Cl:

Number of moles = mass/ molar mass

Number of moles = 15.50 g/ 53.491 g/mol

Number of moles = 0.29 mol

Now we will compare the moles of NH₄Cl with AgCl .

NH₄Cl : AgCl

1 : 1

0.29 : 0.29

Theoretical yield of AgCl:

Mass = number of moles × molar mass

Mass = 0.29 mol ×143.32 g/mol

Mass = 41.56 g

4 0

3 years ago