Help me on a and b pls

Identify a type of strong intermolecular force that exists between water molecules, but does not exist between carbon dioxide mo

timurjin [86]

Intermolecular forces of attraction hold the molecules together. These forces determine the physical properties of substances like melting and boiling points. There are five types of intermolecular forces: Hydrogen bonding, dipole-dipole interactions, ionic interactions, ion-dipole interactions and dispersion forces.

Hydrogen bonding is a stronger force of attraction between hydrogen atom and an electronegative atom (F, N, and O). So, water molecules exhibit hydrogen bonding.

In carbon dioxide molecules, although each C=O is polar the molecule as a whole will be non polar due to symmetry. Therefore, the only intermolecular forces in CO2 will be dispersion forces.

Hence, Hydrogen bonding exists between water molecules but not carbon dioxide molecules.

7 0

3 years ago

Vinegar has a ph of 2 physical or chemical?

ddd [48]

With a pH of 2, it's very acidic and far from a neutral pH and basic. I would say chemical as my answer.

6 0

3 years ago

Read 2 more answers

Find the volume of the rock in the images by the amount of water that it displaces

lyudmila [28]

The volume of the rock is 150

8 0

2 years ago

Hydrogen gas (a potential future fuel) can be formed by the reaction of methane with water according to the following equation:

rusak2 [61]

Answer:

60.42% is the percent yield of the reaction.

Explanation:

Moles of methane gas at 734 Torr and a temperature of 25 °C.

Volume of methane gas = V = 26.0 L

Pressure of the methane gas = P = 734 Torr = 0.9542 atm

Temperature of the methane gas = T = 25 °C = 298.15 K

Moles of methane gas = n

$PV=nRT$

$n=\frac{PV}{RT}=\frac{0.9542 atm\times 26.0L}{0.0821 atm L/mol K\times 298.15 K}=1.0135 mol$

Moles of water vapors at 700 Torr and a temperature of 125 °C.

Volume of water vapor = V' = 23.0 L

Pressure of water vapor = P' = 700 Torr = 0.9100 atm

Temperature of water vapor = T' = 125 °C = 398.15 K

Moles of water vapor gas = n'

$P'V'=n'RT'$

$n'=\frac{PV}{RT}=\frac{0.9100 atm\times 23.0L}{0.0821 atm L/mol K\times 398.15 K}=0.6402 mol$

$CH_4(g)+H_2O(g)\rightarrow CO(g)+3H_2(g)$

According to reaction , 1 mol of methane reacts with 1 mol of water vapor. As we can see that moles of water vapors are in lessor amount which means it is a limiting reagent and formation of hydrogen gas will depend upon moles of water vapors.

According to reaction 1 mol of water vapor gives 3 moles of hydrogen gas.

Then 0.6402 moles of water vapor will give:

$\frac{3}{1}\times 0.6402 mol=1.9208 mol$ of hydrogen gas

Moles of hydrogen gas obtained theoretically = 1.9208 mol

The reaction produces 26.0 L of hydrogen gas measured at STP.

At STP, 1 mole of gas occupies 22.4 L of volume.

Then 26 L of volume of gas will be occupied by:

$\frac{1}{22.4 L}\times 26 L= 1.1607 mol$

Moles of hydrogen gas obtained experimentally = 1.1607 mol

Percentage yield of hydrogen gas of the reaction:

$\frac{Experimental}{Theoretical}\times 100$

$\%=\frac{ 1.1607 mol}{1.9208 mol}\times 100=60.42\%$

60.42% is the percent yield of the reaction.

8 0

4 years ago

GIVING BRAINLISTED

Mice21 [21]

Answer: one molecule of O2.

Explanation: sweet i just took a guess but I believe that if 3 o2 molecules - 2 h2 molecules I think that its just basic maths and it is C because 3-2 = 1 and its o2 remaining, sorry if I’m wrong.

6 0

3 years ago