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Vedmedyk [2.9K]
2 years ago
9

Explain why the middle portion of ship shows more rust than either the top most or the bottom most part ​

Chemistry
1 answer:
LekaFEV [45]2 years ago
8 0

Answer:

A ship comprises of both visible as well as invisible parts. . The most forward part of a ship is called a Bow, the left-hand side of . at a topmost accessible height of the ship and just above the bridge . The mast is a rangy spar arrangement which is elevated more or less vertically to the Centre line of a ship .

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What metal will have properties most similar to those of chromium (Cr)? Why?
garri49 [273]
That element is manganese. As they are in same horizontal row (period) and are next to each other. That is why they show same properties. 

Hope this helps xox :)
5 0
3 years ago
I break and shatter easily and I am not shiny. What am I?
Troyanec [42]

Answer:

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7 0
2 years ago
Aluminum and oxygen react according to the following equation: 4Al + 3O2 -> 2Al2O3 In a certain experiment, 4.6g Al was react
stiv31 [10]

Answer:

Percent yield: 78.2%

Explanation:

Based on the reaction:

4Al + 3O₂ → 2Al₂O₃

<em>4 moles of Al produce 2 moles of Al₂O₃</em>

<em />

To find percent yield we need to find theoretical yield (Assuming a yield of 100%) and using:

(Actual yield (6.8g) / Theoretical yield) × 100

Moles of 4.6g of Al (Molar mass: 26.98g/mol) are:

4.6g Al × (1mol / 26.98g) = 0.1705 moles of Al.

As 4 moles of Al produce 2 moles of Al₂O₃, theoretical moles of Al₂O₃ obtained from 0.1705 moles of Al are:

0.17505 moles Al × (2 moles Al₂O₃ / 4 moles Al) = <em>0.0852 moles of Al₂O₃</em>,

In grams (Molar mass Al₂O₃ = 101.96g/mol):

0.0852 moles of Al₂O₃ × (101.96g / mol) =

<h3>8.7g of Al₂O₃ can be produced (Theoretical yield)</h3>

Thus, Percent yield is:

(6.8g / 8.7g) × 100 =

<h3>78.2% </h3>
8 0
3 years ago
Draw the structure for 1-nitrobutane, making sure to add all non-zero formal charges.
TiliK225 [7]

The molecular structure of 1-nitrobutane is C_{4} H_{9} NO_{2}. The structure of 1-nitrobutane is shown below.

An atom's formal charge would be determined by the covalent model of chemical bonding, which assumes that almost all chemical bonds include equal sharing of electrons among all atoms, regardless their relative electronegativity.

The structure for 1-nitrobutane, making sure to add all non-zero formal charges

There are four kind of molecule present in 1-nitrobutane and they are carbon, hydrogen , nitrogen and oxygen. Nitrogen is bonded with two oxygen atom out of them one oxygen atom is attached with single bond and second oxygen atom is bonded with double bond. Nitrogen has positive charge whereas oxygen has negative charge.

It is a kind of alkane in with nitro group is attached with alkane group.

To know more about 1-nitrobutane

brainly.com/question/25045923

#SPJ4

7 0
2 years ago
What do all viruses have in common? Choose more than one answer.
vitfil [10]

Answer:

1, 3, 4, and 5

Explanation:

the number would be the dot order!

7 0
3 years ago
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