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Vedmedyk [2.9K]
1 year ago
9

Explain why the middle portion of ship shows more rust than either the top most or the bottom most part ​

Chemistry
1 answer:
LekaFEV [45]1 year ago
8 0

Answer:

A ship comprises of both visible as well as invisible parts. . The most forward part of a ship is called a Bow, the left-hand side of . at a topmost accessible height of the ship and just above the bridge . The mast is a rangy spar arrangement which is elevated more or less vertically to the Centre line of a ship .

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How many grams of NaBr are needed to produce 187 grams of CaBr2
andrey2020 [161]
You will need 96.3g (3sf)
6 0
4 years ago
Read 2 more answers
Active
klio [65]

Option B

Primary productivity is not limited by time

<u>Explanation:</u>

To ecosystems, the productivity of the primary producers is essential because certain bodies generate energy for different existence bodies. Besides the era, primary production ends in the extension of dissimilar plant biomass to the practice. Consumers acquire their strength from primary producers, unless directly (herbivores, any detritivores), or diffusely.

It depends superimposed on the availability of the sunlight, availability of the nutrients such as nitrogen, iron, phosphorus from the soil and water. The primary productivity of the plant's distinct autotrophs is not restricted by time.

5 0
3 years ago
The nuclear binding energy of one nitrogen-14 atom is (BLANK) x 10A J. Round to 3
d1i1m1o1n [39]

mass defect = mass of constituents - mass of atom

N has 7p and 9n

proton mass ~ 1.00728 amu

neutron mass ~ 1.00866 amu

electron mass ~ 0.000549 amu

Nitrogen mass ~ 14.003074 amu

mass defect = (7*1.00728)-(7*1.00866)-(7*0.000549) - 14.003074

= 0.11235amu

convert to energy, the binding energy = 1.68x10^-11 J


5 0
3 years ago
How many formula units of sodium chloride (NaCl) may theoretically be produced from 13.0 g FeCl3?
algol [13]

Answer:

1.445\times 10^{23} formula units of sodium chloride can be formed from 13.0 gram of ferric chloride.

Explanation:

Mass of ferric chloride = 13.0 g

Moles of ferric chloride = \frac{13.0 g}{162.5 g/mol}=0.08 mol

1 mole of ferric chloride has three moles of chloride ions.Then 0.08 moles of ferric chloride will have :

3\times 0.08 mol=0.24 mol of chloride

Na^++Cl^-\rightarrow NaCl

1 mole of sodium ion reacts with 1 mole of chloride ion to form 1 mole of NaCl. Then 0.24 moles of chloride ion will give:

\frac{1}{1}\times 0.24 mol=0.24 mol of NaCl

1 mole = N_A=6.022\times 10^{23} molecules/ atoms

Number of NaCl molecules in 0.24 moles :

=6.022\times 10^{23}\times 0.24=1.445\times 10^{23} molecules

1.445\times 10^{23} formula units of sodium chloride can be formed from 13.0 gram of ferric chloride.

4 0
3 years ago
Calculate the vapor pressure at 35ºC of a solution made by dissolving 20.2 g of sucrose (C12H22O11)in 60.5 g of water. The vapor
sukhopar [10]

Answer:

P' = 41.4 mmHg → Vapor pressure of solution

Explanation:

ΔP = P° . Xm

ΔP = Vapor pressure of pure solvent (P°) - Vapor pressure of solution (P')

Xm = Mole fraction for solute (Moles of solvent /Total moles)

Firstly we determine the mole fraction of solute.

Moles of solute → Mass . 1 mol / molar mass

20.2 g . 1 mol / 342 g = 0.0590 mol

Moles of solvent → Mass . 1mol / molar mass

60.5 g . 1 mol/ 18 g = 3.36 mol

Total moles = 3.36 mol + 0.0590 mol = 3.419 moles

Xm = 0.0590 mol / 3.419 moles → 0.0172

Let's replace the data in the formula

42.2 mmHg - P' = 42.2 mmHg . 0.0172

P' = - (42.2 mmHg . 0.0172 - 42.2 mmHg)

P' = 41.4 mmHg

5 0
3 years ago
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