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Alchen [17]
3 years ago
10

Would a tighter or a looser cover heat the oven faster? How about no covering at all?

Chemistry
1 answer:
victus00 [196]3 years ago
4 0
A tighter cover because of the gas particles , the gas particles would be trapped causing it to heat up faster. no covering at all would make it heat up the slowest
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draw the lewis structure for CO2, H2CO3, HCO3-, and CO3 2-.Rank these in order of increasing attraction to water molecules. Expl
gavmur [86]

Answer:

The structures are attached in file.

Hydrogen bonding and intermolecular forces is the reason for ranks allotted.

Explanation:

In determining Lewis structure, we calculate the overall number of valence electrons available for bonding.  Making carbon (the least electronegative atom) the central atom in the structure, we allocate valence electrons until each atom has achieved stability.

In order of decreasing affinity to water molecules:

CO_{3}^{2-}  > HCO_{3} ^{2-} > H_{2} CO_{3}

This is due to the fact that the CO_{3}^{2-}will accept protons more readily than the bicarbonate ion, HCO_{3} ^{2-}. Carbonic acid, H_{2} CO_{3} will not accept any more protons, hence it is the least attractive to water molecule, even though soluble.

3 0
3 years ago
Balance chemical equation Fe3O4 = Fe + CO2
m_a_m_a [10]

equation Fe3O4=Fe+CO2 is an impossible reaction

5 0
4 years ago
One mole of carbon will have the same number of particles as one mole of hydrogen.
AVprozaik [17]
And the answer is False,it does not have the same number with particles as the one mole of hydrogen.
3 0
4 years ago
Read 2 more answers
I dont get it help brainlest
Rufina [12.5K]

Answer:

d is the answer of this question

7 0
2 years ago
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When the potential difference across a lamp is 3.3V the current is 0.15 calculate the resistance of the lamp and give the unit
marissa [1.9K]

Answer:

22Ω

Explanation:

Given parameters:

Potential difference  = 3.3V

Current  = 0.15A

Unknown:

Resistance  = ?

Solution:

According to ohm's law, potential difference, current and resistance are related by the expression below;

             V = I R

where V is the voltage

           I is the current

          R is the resistance

          3.3 = 0.15 x R

             R = \frac{3.3}{0.15}   = 22Ω

6 0
3 years ago
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