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3 years ago

Write application of isotopes .

Chemistry

2 answers:

SCORPION-xisa [38]3 years ago

6 0

Answer:

In the chemical industry.

4vir4ik [10]3 years ago

6 0

Isotopes are the atoms of the same element with same atomic no: and different mass numbers. ... ⇒As isotope of uranium is used as a fuel in nuclear reactor. ⇒An isotope of iodine is used in the treatment of goitre. ⇒An isotope of cobalt is used in the treatment of cancer.

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How can we keep our voices in tip top shape? Please list the three things we can do to help our voices. Which would you say is m

Alisiya [41]

Answer:

help our vocos

Explanation:

5 0

3 years ago

A certain substance X has a normal freezing point of -6.4 C and a molal freezing point depression constant Kf= 3.96 degrees C.kg

Brut [27]

Answer: $1.0\times 10^2g$

Explanation:

Depression in freezing point is given by:

$\Delta T_f=i\times K_f\times m$

$\Delta T_f=T_f^0-T_f=(-6.4-(13.6))^0C=7.2^0C$ = Depression in freezing point

i= vant hoff factor = 1 (for non electrolyte like urea)

$K_f$ = freezing point constant = $3.96^0C/m$

m= molality

$\Delta T_f=i\times K_f\times \frac{\text{mass of solute}}{\text{molar mass of solute}}\times \text{weight of solvent in kg}}$

Weight of solvent (X)= 950 g = 0.95 kg

Molar mass of non electrolyte (urea) = 60.06 g/mol

Mass of non electrolyte (urea) added = ?

$7.2=1\times 3.96\times \frac{xg}{60.06 g/mol\times 0.95kg}$

$x=1.0\times 10^2g$

Thus $1.0\times 10^2g$ urea was dissolved.

8 0

4 years ago

What mass of CO was used up in the reaction with an excess of oxygen gas if 24.7g of carbon dioxide is formed? 2 CO + O2 > 2

Zolol [24]

Balance Chemical Equation,
2 CO + O₂ → 2CO₂
Acc. to this reaction,
88 g (2 mole) of CO₂ was produced when = 56 g (2 mole)of CO was reacted
So,
24.7 g of CO₂ will be produced by reacting = X g of CO

Solving for X,
X = (56 g × 24.7 g) ÷ 88 g

X = 2.26 g ÷ 88 g

X = 0.0257 g of CO

Result:
0.0257 g of CO is required to be reacted with excess of O₂ to produce 24.7 g of CO₂.

7 0

3 years ago

Calculate the molarity of a solution prepared by dissolving 1.495 moles of lioh in enough water to give a final volume of 750. m

zhenek [66]

Molarity can be defined as the number of moles of substance dissolved in 1 L of solution.
In the given question ,
number of LiOH moles - 1.495 mol
Dissolved volume - 750 mL
molarity is calculated for 1 L = 1000 mL
In 750 mL - 1.495 mol of LiOH is dissolved
Therefore in 1000 mL - 1.495 mol / 750 mL x 1000 = 1.99 mol

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3 years ago

What is the term for a procedure that allows scientists to obtain good clear analysis and draw

rusak2 [61]

Answer is D(An experiment

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3 years ago