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nydimaria [60]
2 years ago
10

Identify the limiting reactant when 9.65-g H2SO4 reacts with 6.10-g of NaOH.

Chemistry
1 answer:
Masteriza [31]2 years ago
5 0

Answer:

3.56

Explanation:

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Physical or chemical change? what gave you the idea that it was such? ​
Nana76 [90]

Answer:

Chemical Change

Explanation:

It changes color and produces vapor when the foil is added to the solution.

3 0
3 years ago
Read 2 more answers
What is the mass of 6.78x1050 molecules of NaCl
ryzh [129]

Answer:

Explanation:

As

Molar mass of NaCl= 58.44 gm

So we got it that,

58.44 mass of NaCl contain = 6.023*10^23  molecules of Na Cl

x mass will contain = 6.78*10^50

by cross multiplication , we get

x=  58.44*(6.78*10^50)/  6.023*10^23  

x= 65.785 * 10^27  molecules

Plz Brain-list\support me by Subscribing my channel "ZK SOFT&GAMING"

6 0
3 years ago
If the p-side has a higher doping concentration, explain how to keep tuning to the same radio channel?
zzz [600]

Answer:

increase in temperature of the intrinsic semiconductor

Explanation:

  • If the p-side has a higher doping concentration, it implies that number of holes (positive ion) increased which is greater than number of electron (negative ion) in the n-side
  • in order to balance the intrinsic concentration, that is to balance the number of holes and electrons which depends on temperature.
  • an increase in the temperature of the intrinsic semiconductor (p-side), increases the number of electron but number of holes remains constant.

A balance in the intrinsic concentration helps in tuning to the same radio channel.

6 0
3 years ago
Steve and Meg are doing an experiment where they need to make 37 grams of Fe2O3. How many grams of Fe would they need ?
Anna11 [10]

Answer:

25.9g

Explanation:

Molecular mass of Fe₂O₃ = (56 * 2) + (16 * 3)

                                          = 112 + 48 = 160

Let's follow the unitary method now

In 160g Fe₂O₃ , there is 112 g Fe

In 1 g  Fe₂O₃ , there is 112 / 160 g Fe

In 37  Fe₂O₃ , we need 112 * 37 / 160

= 25.9 g Fe

5 0
2 years ago
Mixed Practice:
tigry1 [53]

Given

Mass of NO - 824 g

Molar mass of NO - 30.01g/mol

No of moles of NO = Given mass/Molar mass

No of moles of NO = 824/30.01= 27.45 mole

Hence 27.5 moles of NO are formed!

4 0
2 years ago
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