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Luden [163]
3 years ago
12

Which of the following is NOT an example of a chemical change?

Chemistry
2 answers:
puteri [66]3 years ago
5 0
I think it’s C...........
Katyanochek1 [597]3 years ago
4 0

Answer:

hi there !!

B) Water evaporates into steam.

this is correct because only physical state changes, steam can be cooled down to get water again.

You might be interested in
If I have 13 protons and 12 electrons what is my charge?
Mnenie [13.5K]

Answer:

The charge would be +1

Explanation:

Protons have a positive charge while electrons have a negative charge. Therefore, it's simple subtraction. In every case, subtract the number of electrons from the number of protons.

13 - 12 = 1

Therefore the charge is +1

Here's one more example:

If the element chromium (Cr) has 24 protons and 28 electrons, what is its charge? Remember that protons have a positive charge and electrons have a negative charge.

24 - 28 = -4

Charge = -4

It would be written as followed when associating charge with a specific element: Cr^{-4}

If an element has a neutral charge, that means the number of protons and neutrons are the same. If you look at the periodic table of elements, all of the elements listed have a neutral charge. The 0 isn't showed in the corner because it isn't necessary.

Bonus Information:

This isn't related to your question, but I've come across confusions when it comes to particles. Remember that protons (+) and electrons (-) are the only particles that have a charge, therefore, as it says in it's name, neutrons are neutral or have no charge. Neutrons do not contribute to charge, but they do contribute to the <em>mass</em> of an atom. So the number of protons added to the number of neutrons equate to the mass of an atom. Electrons have mass, but it's so miniscule and insignificant that it doesn't even contribute to the overall mass of the atom, so don't count those.

Remember:

C = p - e

M = p + n

C = atomic charge, M = atomic mass, p =protons, n = neutrons, e = electrons

I hope this helps!

7 0
3 years ago
SnI2 ionic or covalent
mixas84 [53]

Tin(II) iodide, also known as stannous iodide, is an ionic tin salt of iodine with the formula SnI2.

3 0
3 years ago
Read 2 more answers
Blood is forced through the body by the
belka [17]
Blood is pumped throughout the body by your heart.  Your heart is the main organ responsible for blood circulation.
8 0
4 years ago
Which object has the greatest velocity? Assume the objects have equal masses.
emmainna [20.7K]
Option c would be the correct answer
5 0
3 years ago
. Determine the standard free energy change, ɔ(G p for the formation of S2−(aq) given that the ɔ(G p for Ag+(aq) and Ag2S(s) are
olga nikolaevna [1]

<u>Answer:</u> The standard free energy change of formation of S^{2-}(aq.) is 92.094 kJ/mol

<u>Explanation:</u>

We are given:

K_{sp}\text{ of }Ag_2S=8\times 10^{-51}

Relation between standard Gibbs free energy and equilibrium constant follows:

\Delta G^o=-RT\ln K

where,

\Delta G^o = standard Gibbs free energy = ?

R = Gas constant = 8.314J/K mol

T = temperature = 25^oC=[273+25]K=298K

K = equilibrium constant or solubility product = 8\times 10^{-51}

Putting values in above equation, we get:

\Delta G^o=-(8.314J/K.mol)\times 298K\times \ln (8\times 10^{-51})\\\\\Delta G^o=285793.9J/mol=285.794kJ

For the given chemical equation:

Ag_2S(s)\rightleftharpoons 2Ag^+(aq.)+S^{2-}(aq.)

The equation used to calculate Gibbs free change is of a reaction is:  

\Delta G^o_{rxn}=\sum [n\times \Delta G^o_f_{(product)}]-\sum [n\times \Delta G^o_f_{(reactant)}]

The equation for the Gibbs free energy change of the above reaction is:

\Delta G^o_{rxn}=[(2\times \Delta G^o_f_{(Ag^+(aq.))})+(1\times \Delta G^o_f_{(S^{2-}(aq.))})]-[(1\times \Delta G^o_f_{(Ag_2S(s))})]

We are given:

\Delta G^o_f_{(Ag_2S(s))}=-39.5kJ/mol\\\Delta G^o_f_{(Ag^+(aq.))}=77.1kJ/mol\\\Delta G^o=285.794kJ

Putting values in above equation, we get:

285.794=[(2\times 77.1)+(1\times \Delta G^o_f_{(S^{2-}(aq.))})]-[(1\times (-39.5))]\\\\\Delta G^o_f_{(S^{2-}(aq.))=92.094J/mol

Hence, the standard free energy change of formation of S^{2-}(aq.) is 92.094 kJ/mol

8 0
3 years ago
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