Is this graph a function?

A single carton of juice costs $4.20. A special offer pack of 3 cartons costs $9.45. Ali bought a special offer pack instead of

fgiga [73]

1 cartons of juice = $4.20

3 single cartons = 4.20 * 3 = $12.60

1 pack = $9.45

He saved 12.60 - 9.45 = $3.15

So, he saved $3.15, compared to the total ($12.60)

To calculate the percentage, we will do a proportion:

3.15 (money saved) : 12.60 (total of 3 single cartons) = x (how much percentage) : 100 (total)

3.15 : 12.6 = x : 100

To calculate x, we will moltiplicate the ends (where we have known numbers) than divide all per 12.6

So

x = (3.15 * 100) / 12.60 = 315 / 12.6 = 25

So the percentage saving is 25%

6 0

4 years ago

If the perimeter of a rectangle is 34 cm and the area is 66 square cm, then what are the dimensions of the rectangle

BigorU [14]

Answer:

No solution

Step-by-step explanation:

Let's write the two pieces of information algebraically.

Perimeter of rectangle is 34cm:

$2l+2w=34$

Area of rectangle is 66cm^2:

$l*w=66$

Since we have two equations and two variables, we can solve for both values.

I'll leave the work for you but there are no valid solutions.

5 0

3 years ago

It’s either ur good at math or pretty I guess god said be pretty

SashulF [63]

Answer:

55

Step-by-step explanation:

9x + 1 = 7x + 13

x = 6

UW = 42+13

= 55

The two triangles are of congruent (SAS)

4 0

3 years ago

The mean cost of a five pound bag of shrimp is 50 dollars with a standard deviation of 8 dollars. If a sample of 56 bags of shri

velikii [3]

Answer:

59.90% probability that the sample mean would differ from the true mean by less than 0.9 dollars

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the Central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean \mu and standard deviation, which is also called standard error $s = \frac{\sigma}{\sqrt{n}}$

In this problem, we have that:

$\mu = 50, \sigma = 8, n = 56, s = \frac{8}{\sqrt{56}} = 1.07$

If a sample of 56 bags of shrimp is randomly selected, what is the probability that the sample mean would differ from the true mean by less than 0.9 dollars

This is the pvalue of Z when X = 50 + 0.9 = 50.9 subtracted by the pvalue of Z when X = 50 - 0.9 = 49.1. So

X = 50.9

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{50.9 - 50}{1.07}$

$Z = 0.84$

$Z = 0.84$ has a pvalue of 0.7995

X = 49.1

$Z = \frac{X - \mu}{s}$

$Z = \frac{49.1 - 50}{1.07}$

$Z = -0.84$

$Z = -0.84$ has a pvalue of 0.2005

0.7995 - 0.2005 = 0.5990

59.90% probability that the sample mean would differ from the true mean by less than 0.9 dollars

3 0

3 years ago

A police officer is using a radar device to check motorists’ speeds. Prior to beginning the speed check, the officer estimates t

liberstina [14]

Answer:

The probability is 0.8704

Step-by-step explanation:

A Binomial distribution apply when we have n identical and independent events with two possible results, success or fail, and a probability p of success and 1-p of fail. Then, the probability that from the n events, x are success is:

$P(x)=\frac{n!}{x!(n-x)!}*p^{x}*(1-p)^{n-x}$

Then, the number of motorist driving more than 5 miles per hour over the speed limit follow a Binomial Distributions, because we have 4 randomly selected motorists with two possible options: they are driving more than 5 miles per hour over the speed limit or they aren't, and the probability that they are driving more that 5 miles per hour over the speed is 0.4.

Finally, the probability P that among 4 randomly selected motorists, the officer will find at least 1 motorist driving more than 5 miles per hour over the speed limit is:

P = P(1) + P(2) + P(3) + P(4)

Where n is equal to 4 and p is equal to 0.4. Replacing the values for every x, we get:

$P(1)=\frac{4!}{1!(4-1)!}*0.4^{1}*(1-0.4)^{4-1}=0.3456$