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Mrac [35]
3 years ago
7

Simplify the expression (5)2. 25 -10 -25 10

Mathematics
2 answers:
Olegator [25]3 years ago
8 0

Answer:

<h2><em><u>10</u></em></h2>

Step-by-step explanation:

<em><u>Given</u></em><em><u> </u></em><em><u>here</u></em><em><u>, </u></em>

(5)2

= 5 × 2.

= <em><u>10 (Ans)</u></em><em><u> </u></em>

grin007 [14]3 years ago
5 0

Answer:

10

Step-by-step explanation:

5 (2) is the same as 5 × 2 which equals 10

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Jim drove 436 miles using 16 gallons of gas. At this rate, how many limes would he drive using 14 gallons of gas?
almond37 [142]
The ratio here is 16:436.
The easiest way to solve this is finding how many miles Jim can drive using just 1 gallon. We can do this by dividing both sides of the ratio by 16.

16÷16 is 1
436÷16 is 27.25
so our new ratio is 1 gallon:27.25 miles.

next we simply multiply both sides by 14.
1x14=14
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3 years ago
First derivative of <br>√{cosec2x).show with full step.​
Mice21 [21]

Answer:

- \sf \displaystyle \:   \frac{ \cos(2x) }{ \sin ^{2} (2x)\sqrt{ \csc(2x) } }

Step-by-step explanation:

we are given a derivative

\displaystyle \:  \frac{d}{dx} ( \sqrt{  \csc(2x) } )

and said to figure out the first derivative

to do so

recall chain rule:

\sf\displaystyle \:  \frac{d}{dx} (f(g(x)) =  \frac{d}{dg} (f(g(x)) \times  \frac{d}{dx} (g)

so we get

\displaystyle \: g(x) =  \csc(2x)

rewrite the derivative using the chain rule:

\displaystyle \:  \frac{d}{dg} ( \sqrt{  g } )  \times  \frac{d}{dx} ( \csc(2x) )

use square root derivative rule to simplify:

\displaystyle \:   \frac{1}{ 2\sqrt{g} }  \times  \frac{d}{dx} ( \csc(2x) )

now we need to again use chain rule composite function derivative to simplify

where we'll take a new function n so we won't mess up two g's and we'll take 2x as n

use composite function derivative to simplify:

\sf \displaystyle \:   \frac{1}{ 2\sqrt{g} }  \times  \frac{d}{dn}( \csc(n) ) \times  \frac{d}{dx} (2x)

use derivative formula to simplify derivatives:

\sf \displaystyle \:   \frac{1}{ 2\sqrt{g} }  \times   - \cot(n)   \csc(n)  \times  2

substitute the value of n:

\sf \displaystyle \:   \frac{1}{ 2\sqrt{g} }  \times   - 2\cot(2x)   \csc(2x)

substitute the value of g:

\sf \displaystyle \:   \frac{1}{ 2\sqrt{ \csc(2x) } }  \times   - 2\cot(2x)   \csc(2x)

now we need our trigonometric skills to simplify

rewrite cot and csc:

\sf \displaystyle \:   \frac{1}{ 2\sqrt{ \csc(2x) } }  \times   - 2 \dfrac{ \cos(2x) }{ \sin(2x) }   \dfrac{1}{ \sin(2x) }

simplify multiplication:

\sf \displaystyle \:   \frac{1}{ \cancel{ \:  2}\sqrt{ \csc(2x) } }  \times    \cancel{- 2} \dfrac{ \cos(2x) }{ \sin ^{2} (2x) }

simplify multiplication:

- \sf \displaystyle \:   \frac{ \cos(2x) }{ \sin ^{2} (2x)\sqrt{ \csc(2x) } }

4 0
3 years ago
Read 2 more answers
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