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Scorpion4ik [409]
3 years ago
9

8. The reason water is polar is because A. in polar molecules atoms share electrons evenly. B. the electrons spend more time cir

cling the oxygen atom than the hydrogens. A. hydrophilic molecules interact with water. B. hydrophobic molecules do not interact with water. C. there is a transfer of electrons from the hydrogen to the oxygen.
Chemistry
1 answer:
pentagon [3]3 years ago
8 0

Answer: option B happens to be correct since we can somewhere say that the electron density is more near oxygen atom which leads to polarization of bond and development of bond.

Explanation:

The reason why the water molecule is polar is due to the electronegativity difference between the Oxygen  and hydrogen atoms.

Oxygen is more electronegative than hydrogen and hence the covalent bond formed between oxygen and hydrogen would be polarized . Since the oxygen is more electronegative than hydrogen so more electron density would remain around oxygen. Due to the bond polarity partial positive and negative charges would develop on the atoms.

Hydrogen would develop a partial positive charge since it is losing its electron density to more electronegative oxygen atom.

Oxygen would develop a partial negative charge as it is gaining electron density from hydrogen due to its more electronegativity.

The development of partial charges on account of polarity differences in polar molecules are not at all complete electron transfer.The bonds are still covalent in nature and the electrons are shared among atoms but just because one of the atoms is more electronegative so it is having more amount of electron density .

Out of the given options option B happens to be correct since we can somewhere say that the electron density is more near oxygen atom which leads to polarization of bond and development of bond.

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The amount of substance present in a certain object with a given half-life in terms of h can be expressed through the equation,

     A(t) = (A(o))(0.5)^(t/h)

where A(t) is the amount of substance after t years and A(o) is the original amount. In this item we are given that A(t)/A(o) is equal to 0.89. Substituting the known values,

     0.89 = (0.5)(t / 5730 years)

The value of t from the equation is 963.34 years.

<em>Answer: 963 years</em>
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4 years ago
A mixture of helium, nitrogen and oxygen has a total pressure of 821 mmHg. The partial pressure of helium is 105 mmHg, and the p
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Answer:

Total partial pressure, Pt = 821 mm Hg

Partial pressure of Helium, P1 = 105 mm Hg

Partial pressure of Nitrogen, P2 = 312 mm Hg

Partial pressure of Oxygen, P3 = ? mm Hg

According to Dalton's law of Partial pressures,

Pt = P1 + P2 + P3

So, <u>P3 = 404 mm Hg</u>

4 0
2 years ago
Ammonia NH3 may react with oxygen to form nitrogen gas and water.4NH3 (aq) + 3O2 (g) \rightarrow 2 N2 (g) + 6H2O (l)If 2.15g of
bagirrra123 [75]

Answer:

NH3 is the limiting reactant

The % yield is 36.1 %

Explanation:

<u>Step 1: </u>Data given

Mass of NH3 = 2.15 grams

Mass of O2 = 3.23 grams

Molar mass of NH3 = 17.03 g/mol

Molar mass of O2 = 32 g/mol

volume of N2 produced = 0.550 L

Temperature = 295 K

Pressure = 1.00 atm

<u>Step 2:</u> The balanced equation:

4NH3 (aq) + 3O2 (g) → 2 N2 (g) + 6H2O (l)

<u>Step 3:</u> Calculate moles of NH3

Moles NH3 = Mass NH3 / Molar Mass NH3

Moles NH3 = 2.15 grams / 17.03 g/mol

Moles NH3 = 0.126 moles

<u>Step 4:</u> Calculate moles of O2

Moles O2 = 3.23 grams / 32 g/mol

Moles O2 = 0.101 moles

<u>Step 5: </u>Calculate the limiting reactant

For 4 moles NH3 consumed, we need 3 moles of O2 to produce, 2 moles of N2 and 6 moles of H2O

NH3 is the limiting reactant. It will completely be consumed ( 0.126 moles).

O2 is in excess, there will be 3/4 * 0.126 = 0.0945 moles consumed

There will remain 0.101 - 0.945 = 0.0065 moles of O2

<u>Step 6:</u> Calculate moles of N2

For 4 moles NH3 consumed, we need 3 moles of O2 to produce, 2 moles of N2 and 6 moles of H2O

For 4 moles NH3 , we'll have 2 moles of N2 produced

For 0.126 moles NH3 consumed, we'll have 0.063 moles of N2 produced.

<u>Step 7</u>: Calculate volume of N2 produced

p*V = n*R*T

⇒ with p = the pressure of the gas = 1.00 atm

⇒ with V = the volume = TO BE DETERMINED

⇒ with n = the number of moles N2 = 0.063 moles

⇒ with R = the gasconstant = 0.08206 L*atm/K*mol

⇒ with T = the temperature = 295

V = (nRT)/p

V = (0.063*0.08206*295)/1

V = 1.525 L = theoretical yield

<u>Step 8:</u> Calculate the % yield

% yield = actual yield / theoretical yield

% yield = (0.550 L / 1.525 L)*100%

% yield = 36.1 %

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