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dem82 [27]
2 years ago
10

If M is the midpoint of segment AB and AM=9x-5 and MB=15-x, what is the length of AB?

Mathematics
1 answer:
kkurt [141]2 years ago
6 0

Answer:

<h2>AB = 8x+10</h2>

Step-by-step explanation:

If M is the midpoint of the segment AB, then <em>AM+MB = AB</em>. Given the following parameters;

AM=9x-5 and MB=15-x

Required parameter

segemnt AB

Substituting the given parameters into the given formula to get AB we will have;

AB = AM+MB

AB = 9x-5+15-x

collect like terms

AB = 9x-x-5+15

AB = 8x+10

<em>Hence the length of segment AB is 8x+10</em>

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For this case we can define the random variable X as the amount of time it takes her to arrive to work and we know that the distribution for X is given by:

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7 0
3 years ago
(m+2)(m+3)=(m+2)(m-2)
Anastaziya [24]
(m+2)(m+3)= (m+2)(m-2)
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⇒ m= -10/5
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