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kakasveta [241]
3 years ago
8

Explain how to balance the chemical equation and classify its reaction type.

Chemistry
2 answers:
jonny [76]3 years ago
8 0

Answer:

#1. Balanced equation: 2C₅H₅ + Fe → Fe(C₅H₅)₂

#2. Type of reaction: Synthesis reaction

Explanation:

Balanced equations are equations that obey the law of conservation of mass.

When an equation is balanced the number of atoms of each element is equal on both side of the equation.

Equations are balanced by putting appropriate coefficients on the reactants and products.

In our case, we are going to put coefficients 2, 1 and 1.

Thus, the balanced equation will be;

2C₅H₅ + Fe → Fe(C₅H₅)₂

This type of a reaction is known as synthesis reaction, in which two or more reactants or compounds combine to form a single compound or product.

Brrunno [24]3 years ago
3 0

Answer:  The balanced chemical equation is given below.

Explanation:

Law of conservation of mass states that mass can neither be created nor be destroyed but it can only be transformed from one form to another form.

This also means that total mass on the reactant side must be equal to the total mass on the product side.

The balanced chemical equation follows:The balanced chemical equation follows:

On reactant side:

Number of carbon atoms = 10

Number of hydrogen atoms = 10

Number of iron atoms = 1

On product side:

Number of carbon atoms = 10

Number of hydrogen atoms = 10

Number of iron atoms = 1

So, the balanced chemical equation is given above.

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Calculate the heat absorbed when 31.6 g of ice at 0°C is completely melted​
attashe74 [19]

Latent heat of fusion for ice is 33600J/k

  • Mass=31.6J/k

Heat absorbed

  • k_f×m
  • 31.6×33600
  • 1061,740mJ
  • 1061J
8 0
2 years ago
An order is given to administer methylprednisolone, an anti-inflammatory drug, by IV at a rate of 36 mg every 30. min . The IV b
tigry1 [53]

Answer:

0.0192 mL per min.

Explanation:

IV rate = 36 mg per 30 min.

IV concentration = 125 mg per 2.0 mL

36 mg per 30 min. IV rate = 36/30 = 1.2 mg per min

If 125 mg methylprednisolone is present in 2.0 mL of the IV nag, how many mL would contain 1.2 mg?

      = 2x1.2/125

                        = 0.0192 mL

<em>Therefore, the flow rate of the IV must be </em><em>0.0192 mL per min</em><em>. in order to be able to deliver 36 mg per 30 min.     </em>

7 0
3 years ago
Consider the reaction X + Z ?
lions [1.4K]

Answer:

X2Z3

Explanation:

Based on the clues, X is a metal and Z is a non-metal.

X could be aluminum and Z would need to be an element from the oxygen family.

8 0
3 years ago
Calculate the number of atoms in 2.5 moles of Si.
Ede4ka [16]

Answer:

\boxed {\boxed {\sf About \ 1.5 * 10^{24} \ atoms \ Si}}

Explanation:

When converting from moles to atoms, we must use Avogadro's number. This number tells us there are 6.022 * 10²³ atoms in 1 mole. We can multiply this number by the number of moles.

First, we must set up Avogadro's number as a ratio.

\frac {6.022 \ * 10^{23} \ atoms \ Si }{1 \ mol \ Si}}

Next, multiply the number of moles by the ratio.

2.5 \ mol \ Si *\frac {6.022 \ * 10^{23} \ atoms \ Si }{1 \ mol \ Si}}

When we multiply, the moles of silicon will cancel.

2.5 * \frac {6.022 \ * 10^{23} \ atoms \ Si }{1}}

Since the denominator of the fraction is 1, we can cancel it out too.

2.5 *  {6.022 \ * 10^{23} \ atoms \ Si }

1.5055 * 10^{24} \ atoms \ Si

The original measurement (2.5 moles) has 2 significant figures (2 and 5). Therefore we must round to 2 sig figs. For this question, 2 sig figs is the tenth place.

The 0 in the hundredth place tells us to leave the 5 in the tenth place.

1.5 * 10^{24} \ atoms \ Si

There are about <u>1.5 * 10²⁴ atoms of silicon.</u>

7 0
3 years ago
4) Find the mass of 1.46 mol of Al2(SO4)3.
ddd [48]

Answer:

1.46mol of Al2(SO4)3 weights 499.5 grams

Explanation:

First we will find the gram formula mass of Al2(SO4)3.

Al * 2 = 26.98 g/mol * 2 = 53.96 g

SO4 * 3 = 96.06 g/mol * 3 = 288.18

53.96 + 288.18 = 342.14 g

That is the mass of 1 mol of AL2(SO4)3.

Now we will multiply 342.14g by 1.46.

342.14 * 1.46 = 499.5244 g

Or ... 499.5 g

8 0
2 years ago
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