Latent heat of fusion for ice is 33600J/k
Heat absorbed
- k_f×m
- 31.6×33600
- 1061,740mJ
- 1061J
Answer:
0.0192 mL per min.
Explanation:
IV rate = 36 mg per 30 min.
IV concentration = 125 mg per 2.0 mL
36 mg per 30 min. IV rate = 36/30 = 1.2 mg per min
If 125 mg methylprednisolone is present in 2.0 mL of the IV nag, how many mL would contain 1.2 mg?
= 2x1.2/125
= 0.0192 mL
<em>Therefore, the flow rate of the IV must be </em><em>0.0192 mL per min</em><em>. in order to be able to deliver 36 mg per 30 min. </em>
Answer:
X2Z3
Explanation:
Based on the clues, X is a metal and Z is a non-metal.
X could be aluminum and Z would need to be an element from the oxygen family.
Answer:

Explanation:
When converting from moles to atoms, we must use Avogadro's number. This number tells us there are 6.022 * 10²³ atoms in 1 mole. We can multiply this number by the number of moles.
First, we must set up Avogadro's number as a ratio.

Next, multiply the number of moles by the ratio.

When we multiply, the moles of silicon will cancel.

Since the denominator of the fraction is 1, we can cancel it out too.


The original measurement (2.5 moles) has 2 significant figures (2 and 5). Therefore we must round to 2 sig figs. For this question, 2 sig figs is the tenth place.
The 0 in the hundredth place tells us to leave the 5 in the tenth place.

There are about <u>1.5 * 10²⁴ atoms of silicon.</u>
Answer:
1.46mol of Al2(SO4)3 weights 499.5 grams
Explanation:
First we will find the gram formula mass of Al2(SO4)3.
Al * 2 = 26.98 g/mol * 2 = 53.96 g
SO4 * 3 = 96.06 g/mol * 3 = 288.18
53.96 + 288.18 = 342.14 g
That is the mass of 1 mol of AL2(SO4)3.
Now we will multiply 342.14g by 1.46.
342.14 * 1.46 = 499.5244 g
Or ... 499.5 g