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grin007 [14]
2 years ago
11

An order is given to administer methylprednisolone, an anti-inflammatory drug, by IV at a rate of 36 mg every 30. min . The IV b

ag contains 125 mg of methylprednisolone in every 2.0 mL . What should the flow rate be in milliliters per minute (mL/min)?
Chemistry
1 answer:
tigry1 [53]2 years ago
7 0

Answer:

0.0192 mL per min.

Explanation:

IV rate = 36 mg per 30 min.

IV concentration = 125 mg per 2.0 mL

36 mg per 30 min. IV rate = 36/30 = 1.2 mg per min

If 125 mg methylprednisolone is present in 2.0 mL of the IV nag, how many mL would contain 1.2 mg?

      = 2x1.2/125

                        = 0.0192 mL

<em>Therefore, the flow rate of the IV must be </em><em>0.0192 mL per min</em><em>. in order to be able to deliver 36 mg per 30 min.     </em>

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3 years ago
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If the container is closed and the ethanol is allowed to reach equilibrium with its vapor, how many grams of liquid ethanol rema
SVETLANKA909090 [29]

Explanation:

Let us assume that the given data is as follows.

        V = 3.10 L,        T = 19^{o}C = (19 + 273)K = 292 K

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So,     P = \frac{40 torr}{760 torr} \times 1 atm

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          n = ?

According to the ideal gas equation, PV = nRT.

Putting the given values into the above equation to calculate the value of n as follows.

                 PV = nRT

   0.053 atm \times 3.10 L = n \times 0.0821 L atm/mol K \times 292 K

                 0.1643 = n \times 23.97

                    n = 6.85 \times 10^{-3}

It is known that molar mass of ethanol is 46 g/mol. Hence, calculate its mass as follows.

               No. of moles = \frac{mass}{\text{molar mass}}

                 6.85 \times 10^{-3} = \frac{mass}{46 g/mol}  

                    mass = 315.1 \times 10^{-3} g

                              = 0.315 g

Thus, we can conclude that the mass of liquid ethanol is 0.315 g.

4 0
3 years ago
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8 0
3 years ago
Can Someone help me pls?
Ilia_Sergeevich [38]

Answer:

For H3O concentration you do 10^-pH so if pH is 5 then H3O+ is 10^-5= 1*10^-5 H3O+ ions

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