The intermolecular interactions found between pentane molecules are London-Dispersion Forces.
Explaination:
Step 1:
Instantaneous Dipole: As the pentane molecule is non polar in nature and the electron density on each molecule is symmetrical. When this symmetrical molecule approaches second symmetrical molecule there disturbance is caused due to repulsion between electrons. Due to repulsion the electrons changes there position and for a small period of time an instantaneous dipole is produced on pentane molecule.
Step 2:
Induced Dipole: The dipole produced in step one when approaches another symmetrical pentane molecule, the partial positive part (low electron density site) attracts the electron from symmetrical pentane and induces polarity in it.
In this way the process repeats and interactions are developed between the non polar pentane molecules.
A gauge records the pressure over atmospheric pressure (0kpa on the gauge is actually the atmospheric pressure and a reading of 276kpa is 276kpa over atmospheric pressure). That means that means that to find absolute pressure you just add atmospheric pressure (around 1atm (101kpa)) to 286kpa to get 387kpa. I hope this helps.
Answer:
Cr
Explanation:
Cr will displace Sn from compound because Cr is higher than Sn in the electrochemical series of metals
<u>Given: </u>
Radius of culvert, r = 0.5 m
Tangential acceleration of the truck, a = 3 m/s2
<u>To determine:</u>
The angular acceleration, α
<u>Explanation:</u>
The tangential acceleration is related to the angular acceleration through the radius as:
a = rα
α = a/r = 3 ms⁻²/0.5 m = 6 s⁻²
Ans: The angular acceleration is 6 s⁻²
Answer:
C₂ = 0.52 M
Explanation:
Given data:
Initial volume = 334.75 mL
Initial concentration = 1.28 M
Final volume = 822.18 mL
Final concentration = ?
Solution:
C₁V ₁ = C₂V₂
By putting values,
1.28 M×334.75 mL = C₂×822.18 mL
C₂ = 1.28 M×334.75 mL / 822.18 mL
C₂ = 428.48 M.mL / 822.18 mL
C₂ = 0.52 M
