ANSWER ONLY IF U KNOW I RLLY NEED HELP THIS IS THE LAST OF MY POINTS.

Oliga [24]

Answer:

the answer is 0.34 (look down to see a trick to find a fast answer0

Step-by-step explanation:

Remember, when people say 34%, it means 34% of 1. So, 34% is equivalent to .34. We multiply 50 by .34 to get 34% of 50. So, 34% of 50 is 17

Percentages are communative. 34% of 50 is the same as 50% of 34.

3 0

3 years ago

Read 2 more answers

Explain the following types of angles:

ZanzabumX [31]

Answer:

acute angle measure less than 90 degrees, right angle measure 90 degrees, Obtuse angle measure more than 90 degrees, straight angle equal to 180 degrees, reflex angle is an angle greater than 180° and less than 360°, complementary angle either of two angles whose sum is 90°, supplementary angle either of two angles whose sum is 180°

6 0

2 years ago

What is 51/2-7 equal

pantera1 [17]

Answer:

give me brainliest

Step-by-step explanation:

37/2 = 18.50000

8 0

3 years ago

Please help! I’ll mark as BRAINLIEST :))

kaheart [24]

Step-by-step explanation:

could the conditional statement be written in another way

6 0

4 years ago

The mayor of a town has proposed a plan for the construction of an adjoining bridge. A political study took a sample of 1700 vot

lara [203]

Answer:

$z=\frac{0.66 -0.63}{\sqrt{\frac{0.63(1-0.63)}{1700}}}=2.562$

$p_v =P(z>2.562)=0.0052$

So the p value obtained was a very low value and using the significance level given $\alpha=0.02$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can say that at 2% of significance the proportion of voters that favored construction is higher than 0.63 or 63%.

Step-by-step explanation:

Data given and notation

n=1700 represent the random sample taken

$\hat p=0.66$ estimated proportion of voters that favored construction

$p_o=0.63$ is the value that we want to test

$\alpha=0.02$ represent the significance level

Confidence=98% or 0.98

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that percentage of residents who favor construction is more than 63%.:

Null hypothesis: $p \leq 0.63$

Alternative hypothesis: $p > 0.63$

When we conduct a proportion test we need to use the z statisitc, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.66 -0.63}{\sqrt{\frac{0.63(1-0.63)}{1700}}}=2.562$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.02$ . The next step would be calculate the p value for this test.

Since is a right tailed test the p value would be:

$p_v =P(z>2.562)=0.0052$

So the p value obtained was a very low value and using the significance level given $\alpha=0.02$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can say that at 2% of significance the proportion of voters that favored construction is higher than 0.63 or 63%.

7 0

3 years ago