All categories

3 years ago

ANSWER ONLY IF U KNOW I RLLY NEED HELP THIS IS THE LAST OF MY POINTS.

Mathematics

2 answers:

Ostrovityanka [42]3 years ago

7 0

Sure the answer is 2 4.5

lora16 [44]3 years ago

6 0

Answer:

Slope = 5/4

Y-intercept = 2

You might be interested in

If the volume of a storage container is 6720 cubic inches, what is the height of the container

guajiro [1.7K]

18.87 inches the cube root of 6720

6 0

3 years ago

. An object dropped from a height of 200 meters has a height, h(t), in meters after t seconds have lapsed, such that h(t) = 200

Veronika [31]

Answer:

t(h)= (h-200)/-4.9

The time to reach a height of 50 meters is 30.6 seconds

Step-by-step explanation:

To express t as a function of height (h) we must transform the equation below:

h=200-4.9t

h-200=-4.9t

(h-200)/-4.9=t

t(h)= (h-200)/-4.9

To find the time to reach a height of 50 meters, we must replace this value on the new equation:

t(h)=50-200/-4.9

t(h)= 30.612

The time to reach a height of 50 meters is 30.6 seconds

8 0

4 years ago

2 tan 30°<br>II<br>1 + tan- 300

shusha [124]

Question:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$

Answer:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= sin(60^{\circ})$

Step-by-step explanation:

Given

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$

Required

Simplify

In trigonometry:

$tan(30^{\circ}) = \frac{1}{\sqrt{3}}$

So, the expression becomes:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2 * \frac{1}{\sqrt{3}}}{1 + (\frac{1}{\sqrt{3}})^2}$

Simplify the denominator

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2 * \frac{1}{\sqrt{3}}}{1 + \frac{1}{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\frac{2}{\sqrt{3}}}{1 + \frac{1}{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\frac{2}{\sqrt{3}}}{ \frac{3+1}{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\frac{2}{\sqrt{3}}}{ \frac{4}{3}}$

Express the fraction as:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2}{\sqrt 3} / \frac{4}{3}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2}{\sqrt 3} * \frac{3}{4}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{1}{\sqrt 3} * \frac{3}{2}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{3}{2\sqrt 3}$

Rationalize

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{3}{2\sqrt 3} * \frac{\sqrt{3}}{\sqrt{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{3\sqrt{3}}{2* 3}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\sqrt{3}}{2}$

In trigonometry:

$sin(60^{\circ}) = \frac{\sqrt{3}}{2}$

Hence:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= sin(60^{\circ})$

3 0

3 years ago

Find the volume of each sphere. Be sure to include appropriate units.<br> (Show your work)

babunello [35]

Answer:

2145.5m^3

679.2yard

Step-by-step explanation:

$volume \: of \: a \: sphere = \frac{4}{3}\pi \: r {}^{3} \\ when \: r = 8 \\ volume = \frac{4}{3} \times \frac{22}{7} \times 8 {}^{3} \\ volume = \frac{4}{3} \times \frac{22}{7} \times 8 \times 8 \times 8 \\ volume = \frac{4 \times 22 \times 512}{3 \times 7} \\ volume = \frac{45056}{21} \\ volume = 2145.5m {}^{3} \\ \\ for \: the \: second \: shape \\ volume = \frac{4}{3} \times \frac{22}{7} \times 5.5 {}^{3} \\ = \frac{4}{3} \times \frac{22}{7} \times 166.373 \\ = \frac{14641}{21} \\ = 697.2yard$

6 0

3 years ago

What is the distance between (-4,0)and (-4,-5)

Nastasia [14]

Answer:

<h2><em><u>ᎪꪀsωꫀᏒ</u></em></h2>

5 units

Step-by-step explanation:

$\sf{}$

4 0

3 years ago