An appropriate use of social media includes: C. having thought-provoking debates.
<h3>What is
social media?</h3>
Social media refers to a collection of Internet software applications which are designed and developed so as to avail end users an ability to add, share and discuss different information, as well as enhance collaboration and debates between community members over the Internet.
In this context, we can logically deduce that having thought-provoking debates and making constructive posts are appropriate use of social media.
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Answer:
return tmp;
default:
tmp . token_type = ERROR;
return tmp;
1. In the code, input.GetChar() gets the next character from standard input. If GetToken() is called four times, which of the following inputs will return a token whose type is ERROR?
A. ========
A. =<======
B. ===>====
C. =====<==
D. ======<=
Answer:
Testing that super user (SYSADMIN) access is limited to only appropriate personnel.
Explanation:
A test for logical access at an organization being audited would include testing that super user (SYSADMIN) access is limited to only appropriate personnel.
Answer:
Explanation:
The following program creates a function called region_Matches that takes in two strings as arguments as well as an int for starting point and an int for amount of characters to compare. Then it compares those characters in each of the words. If they match (ignoring case) then the function outputs True, else it ouputs False. The test cases compare the words "moving" and "loving", the first test case compares the words starting at point 0 which outputs false because m and l are different. Test case 2 ouputs True since it starts at point 1 which is o and o.
class Brainly {
public static void main(String[] args) {
String word1 = "moving";
String word2 = "loving";
boolean result = region_Matches(word1, word2, 0, 4);
boolean result2 = region_Matches(word1, word2, 1, 4);
System.out.println(result);
System.out.println(result2);
}
public static boolean region_Matches(String word1, String word2, int start, int numberOfChars) {
boolean same = true;
for (int x = 0; x < numberOfChars; x++) {
if (Character.toLowerCase(word1.charAt(start + x)) == Character.toLowerCase(word2.charAt(start + x))) {
continue;
} else {
same = false;
break;
}
}
return same;
}
}
The comments the Teacher leaves on the old test are usually the correct answers