Answer:
0.903264
Step-by-step explanation:
Given that a TV set contains five circuit boards of type A, five of type B, and four of type C. The probability of failing in its first 5000 hours of use is 0.03 for a type A circuit board, 0.04 for a type B circuit board, and 0.03 for a type C circuit board.
Let A' = the event that A fails, B' = B fails and C'= C fails.
Probability that no circuit board fails = Prob (A'B'C')
= P(A')P(B')P(C') (since A,B, C are independent, their complements are independent
= (1-0.03)(1-0.04)(1-0.03)
= 0.903264
Answer:
340/4
Step-by-step explanation:
i beleive the answer would be 340 = 4 but if 340/4 is an option you could choose it.
Answer:
estudia porque para pendej0 no se estudia
Step-by-step explanation:
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