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notka56 [123]
3 years ago
6

A bungee cord with a spring constant of 800 StartFraction N over m EndFraction stretches 6 meters at its greatest displacement.

How much elastic potential energy does the bungee cord have? The bungee cord has J of elastic potential energy.
Physics
1 answer:
zalisa [80]3 years ago
8 0

Explanation:

EE = ½ kx²

EE = ½ (800 N/m) (6 m)²

EE = 14,400 J

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No because point A has to be higher for more KE to push the object and make the look
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What energy does black holes give off? A) photons B) dark matter C) dark energy D) none of the above
Umnica [9.8K]

never seen one although i guess the elegant answer is D) none of the mentioned posibilities

6 0
3 years ago
Read 2 more answers
A boy and a girl are balanced on a massless seesaw. The boy has a mass of 60 kg and the girl's mass is 50 kg. If the boy sits 1.
skelet666 [1.2K]

Answer: 1.8m

Explanation:

Using the principle of moment to solve the question which states that the sum of clockwise moment is equal to the sum of anticlockwise moments.

The boy moves in the clockwise direction towards the pivot while the girl moves in the anticlockwise direction towards the pivot.

Since moment = force × perpendicular distance

CW moments = 60×1.5 = 90Nm

ACW moments = 50×x = 50x

Equating both moments to get 'x'

90 = 50x

x =9/5

x = 1.8m

This shows that the girl must sit 1.8m from the other side for equilibrium.:

3 0
3 years ago
In a scientific experiment, how many independent variables should be tested at the same time? a none. Independent variables are
Volgvan

Answer:

D

Explanation:

It is important that we have two variables, Independent

and Dependant Variable.

8 0
3 years ago
At a given location the airspeed is 20 m/s and the pressure gradient along the streamline is 100 N/m3. Estimate the airspeed at
Degger [83]

Answer:

17.97m/s

Explanation:

Density of air (ρ)air=1.23 kg/m3, and

Air speed (V) =20 m/sec, pressure gradient along the streamline, ∂p/∂x = 100N/m^3.

The equation of motion along the stream line directions:

considering the momentum balance along the streamline.

γsinθ-∂p/∂x=ρV(∂V/∂x)

Neglecting the effect of gravity , then γ=ρg=0

So, ∂p/∂x= -ρV(∂V/∂x)

∂V/∂x= - 100/(20X1.23)= -4.0650407/S

Also δV/δx=∂V/∂x

∂V/∂x=-4.0650407/S and δx=0.5 m

δV = (-4.0650407/S) *(0.5m)

δV = -2.0325203 m/S

So net air speed will be V+δV= -2.0325203+20 ≅17.96748 m/s

Approximately, V+δV=17.97m/s.

8 0
3 years ago
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