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3 years ago

PLEASE I WLL GIVE BRAINLIEST JUST HELPS MEEEEE OMG IM ON MY SECOND ATTEMPT PLS PLS PLS HELP

Mathematics

1 answer:

worty [1.4K]3 years ago

6 0

Answer:

$\purple { \bold{ \frac{ (x - 3)}{3x - 18} }}$

Step-by-step explanation:

$\frac{x + 3}{ {x}^{2} + 7x + 12 } . \frac{ {x}^{2} + x - 12}{3x - 18} \\ \\ = \frac{x + 3}{ {x}^{2} + 4x + 3x + 12 } . \frac{ {x}^{2} + 4x - 3x - 12}{3(x - 6)} \\ \\ = \frac{x + 3}{ {x}(x + 4) + 3(x + 4) } . \frac{ {x}(x + 4) - 3(x + 4)}{3(x - 6)} \\ \\ = \frac{ \cancel{(x + 3)}}{ (x + 4) \cancel{(x + 3)} } . \frac{ (x + 4) (x - 3)}{3(x - 6)} \\ \\ = \frac{1}{ \cancel{ (x + 4)} } . \frac{ \cancel{ (x + 4)} (x - 3)}{3(x - 6)} \\ \\ \red{ \bold{= \frac{ (x - 3)}{3x - 18} }}\\ \\$

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There is a 21.053% probability that this person made a day visit.

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There is a 39.474% probability that this person made a two night visit.

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What is the probability of B happening, knowing that A has happened.

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Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

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P(A) is the probability that the person made a purchase. So $P(A) = 0.38$

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There is a 21.053% probability that this person made a day visit.

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What is the probability that this person made a one night visit, given that she made a purchase?

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There is a 39.474% probability that this person made a two night visit.

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