Question

What’s the answer??????#9

Answer 1

$\huge \tt \color{cyan}{➢}\color{pink}{A}\color{blue}{n}\color{red}{s}\color{green}{w}\color{grey}{e}\color{purple}{r }\color{cyan}{➢}$

$\large\underline{ \boxed{ \sf{✰\:Important\: point's }}}$

• a polynomial equation of the second degree is said to be as quadratic equation.
• quadratic:-a function, of the form y=ax²+bx+c.
• Standard form of quadratic equation is ax²- bx+c=0
• where a≠0

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$\large\underline{ \boxed{ \sf{✰\: Let's\: solve }}}$

$\purple{ \sf{⇒Given \:function}}$

⇒ y = -2(x-5)²-4

• now 1st we have to solve (x-5)² by using algebraic identify (a-b)²= a²+b²-2ab here a=x nd b = -5

1. (x-5)²
2. x²-10x+25

• Now

⇒y = -2(x²-10x+25)-4

• distribution of 2 with bracket

⇒ y= -2x²+20x-50-4

⇒ y= -2x²+20x-54

Hence option A (-2x²+20x-54) is right ans.....

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$\red{ \underline{\underline{ \boxed{ \tt{✰ \: Option \: A \: ✓}}}}}$

Hope it helps !

Answer 2

Answer:

A)

Step-by-step explanation:Quadratics