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klio [65]
3 years ago
8

1 1/5 - 1/2 how do i get this answer?

Mathematics
1 answer:
jeyben [28]3 years ago
6 0

Answer:

7/10

Step-by-step explanation:

1 1/5 -1/2 = 6/5 - 1/2 = 12/10 - 5/10 = 7/10

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Mika's rosebush had 24 blooms in the first week of May. This was 80% as many blooms as Tammy's rosebush had during the same peri
Harrizon [31]
Tammy’s bush would have 30 blooms. 80% of 30 is 24.
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3 years ago
during one day, Ashville had a high temperature of 6 degrees Celsius, and a low temperature of -4 degrees Celsius. what is the d
Lynna [10]
The difference is 10 because its asking you to subtract ( 6 - (-4) = 10 ).
8 0
3 years ago
(a) Cup A has a diameter of 10 cm. and a height of 20 cm. Find the Volume of Cup A.
Oksana_A [137]

The volume of cup A is 1570.8 cm³ while the volume of cup B is 6283 cm³

<h3>Volume</h3>

Volume is the amount of space occupied by a three dimensional object or figure.

The cup has the shape of a cylinder, the volume is:

Volume = π * radius² * height

For cup A:

Volume = π * (10/2)² * 20 = 1570.8 cm³

Let each punch be 1 cm³, the number of cups needed = 1570.8 cm³ / 1 cm³ = 1571

For cup B:

Volume = π * (20/2)² * 20 = 6283 cm³

Let each punch be 1 cm³, the number of cups needed = 6283 cm³ / 1 cm³ = 6283

The volume of cup A is 1570.8 cm³ while the volume of cup B is 6283 cm³

Find out more on Volume at: brainly.com/question/1972490

7 0
3 years ago
Last question I need i have gotten everything else please help me if you can​
Goryan [66]

Answer:

There are 39 people in the Filmmaking club and 25 in the Yearbook Club

X = 39

39x + 25y = 64

Step-by-step explanation:

I really hope this is right, it was kinda confusing! Sorry if I got it wrong!!

3 0
3 years ago
Read 2 more answers
Ammonia, nh3 (delta.hf = –46.2 kj), reacts with oxygen to produce water (delta.hf = –241.8 kj) and nitric oxide, no (delta.hf =
poizon [28]

The enthalpy change (ΔH) for the reaction given the data from the question is –900.8 KJ

<h3>Data obtained from the question</h3>
  • 4NH₃ + 5O₂ —> 6H₂O + 4NO
  • Enthalpy of ammonia, NH₃ = –46.2 KJ
  • Enthalpy of Oxygen = 0 KJ
  • Enthalpy of water, H₂O = –241.8 KJ
  • Enthalpy of nitric oxide, NO = 91.3 KJ
  • Enthalpy change (ΔH) =?

<h3>How to determine the enthalpy change</h3>

ΔHrxn = ∑ΔH(products) - ∑ΔH(reactants)

ΔHrxn = ∑[H(H₂O) + H(NO)] - ∑[H(NH₃) + H(O₂)]

ΔHrxn = [(6 × –241.8) + (4 × 91.3)] – [(4 × –46.2) + (5×0)]

ΔHrxn = –1085.6 + 184.8

ΔHrxn = –900.8 KJ

Learn more about enthalpy change:

brainly.com/question/2364362

#SPJ4

4 0
2 years ago
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