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mars1129 [50]
3 years ago
5

Which is a property of bases?​

Physics
1 answer:
Brrunno [24]3 years ago
3 0

Answer:

to turn red litmus blue and react with acid to form salt

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Look at the diagram showing the different wavelengths in sunlight.
Alex777 [14]

Answer:

Explanation:

They are infrared waves which mean they take the form of heat.

6 0
4 years ago
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The mass of your new motorcycle is 250kg. What is the weight on the moon in newtons
Hunter-Best [27]

Weight of motorcycle on the moon = mg

Here, g= 1.622 m/s²

So, W = 250 * 1.622 = 405.5 Kgm/s² = 405.5 N.

Did you understand??


8 0
3 years ago
A 600 N astronaut travels to an asteroid where the gravitational force is one-hundredth that of Earth. What is the astronaut's w
timurjin [86]
Weight=mass x gravitational force

W=60 x 1/100 x 10
W=60 x 0.1
W=6N
7 0
3 years ago
In order to reduce the amount of energy lost due to heat flow, electricity is delivered to our homes using _____.
erica [24]

In order to reduce the amount of energy lost due to heat flow, electricity is delivered to our homes using <u>d. low current</u>.

<u>Explanation</u>:

The presence of flow of electrons is said to be electricity. The electricity flows in one direction. The electricity enables function of the electrical devices and machines.

Heat is generated when the electricity flows from one place to another. So the energy is lost in the form of heat.

So to avoid the loss of energy, the electricity is delivered to home using low current. The strength of an electric current can be measured and represented in the unit of ampere.

4 0
4 years ago
Read 2 more answers
An ideal Diesel cycle has a compression ratio of 18 and a cutoff ratio of 1.5. Determine the (1) maximum air temperature and (2)
weqwewe [10]

Answer:

(1) The maximum air temperature is 1383.002 K

(2) The rate of heat addition is 215.5 kW

Explanation:

T₁ = 17 + 273.15 = 290.15

\frac{T_2}{T_1} =r_v^{k - 1} =18^{0.4} =3.17767

T₂ = 290.15 × 3.17767 = 922.00139

\frac{T_3}{T_2} =\frac{v_3}{v_2} = r_c = 1.5

Therefore,

T₃ = T₂×1.5 = 922.00139 × 1.5 = 1383.002 K

The maximum air temperature = T₃ = 1383.002 K

(2)

\frac{v_4}{v_3} =\frac{v_4}{v_2} \times \frac{v_2}{v_3}  = \frac{v_1}{v_2} \times \frac{v_2}{v_3} = 18 \times \frac{1}{1.5} = 12

\frac{T_3}{T_4} =(\frac{v_4}{v_3} )^{k-1} = 12^{0.4} = 2.702

Therefore;

T_4 = \frac{1383.002}{2.702} =511.859 \ k

Q_1 = c_p(T_3-T_2)

Q₁ = 1.005(1383.002 - 922.00139) = 463.306 kJ/jg

Heat rejected per kilogram is given by the following relation;

c_v(T_4-T_1)  = 0.718×(511.859 - 290.15) = 159.187 kJ/kg

The efficiency is given by the following relation;

\eta = 1-\frac{\beta ^{k}-1}{\left (\beta -1  \right )r_{v}^{k-1}}

Where:

β = Cut off ratio

Plugging in the values, we get;

\eta = 1-\frac{1.5 ^{1.4}-1}{\left (1.5 -1  \right )18^{1.4-1}}= 0.5191

Therefore;

\eta = \frac{\sum Q}{Q_1}

\therefore 0.5191 = \frac{150}{Q_1}

Heat supplied = \frac{150}{0.5191}  = 288.978 \ hp

Therefore, heat supplied = 215491.064 W

Heat supplied ≈ 215.5 kW

The rate of heat addition = 215.5 kW.

7 0
4 years ago
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