Think it would be c, 5.1 g
Given:
The force of attraction is F = 48.1 N
The separation between the charges is

Also, the magnitude of charge q1 = q2 = q.
To find the magnitude of charge.
Explanation:
The magnitude of charge can be calculated by the formula

Here, k is the Coulomb's constant whose value is

On substituting the values, the magnitude of charge will be

Thus, the magnitude of each charge is 9.91 x 10^(-4) micro Coulombs.
Answer:
When we double the angular velocity the maximum acceleration
will changes by a factor of 4.
Explanation:
Given the angular frequency
of the simple harmonic oscillator is doubled.
We need to find the change in the maximum acceleration of the oscillator.

Now, according to the problem, the angular frequency
got doubled.
Let us plug
. Then the maximum acceleration will be 



We can see, when we double the angular velocity the maximum acceleration will changes by a factor of 4.
The wavelengths of the constituent travelling waves CANNOT be 400 cm.
The given parameters:
- <em>Length of the string, L = 100 cm</em>
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The wavelengths of the constituent travelling waves is calculated as follows;

for first mode: n = 1

for second mode: n = 2

For the third mode: n = 3

For fourth mode: n = 4

Thus, we can conclude that, the wavelengths of the constituent travelling waves CANNOT be 400 cm.
The complete question is below:
A string of length 100 cm is held fixed at both ends and vibrates in a standing wave pattern. The wavelengths of the constituent travelling waves CANNOT be:
A. 400 cm
B. 200 cm
C. 100 cm
D. 67 cm
E. 50 cm
Learn more about wavelengths of travelling waves here: brainly.com/question/19249186