The maximum speed is 0.55 m/s
Explanation:
For an object in uniform circular motion, the force of friction between the object and the ground provides the centripetal force required to keep the body in motion. Therefore we can write:
where the term on the left is the frictional force and the term on the right is the centripetal force, and where
is the coefficient of static friction
m is the mass of the body
g is the gravitational acceleration
v is the speed of the body
r is the radius of the circular path
In this problem, we have:
r = 0.102 m
Substituting and re-arranging, we find the maximum speed v at which the salt shaker can rotate:
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From the law of the conservation of energy; the ratio of the total kinetic energy after the collision to the total kinetic energy before the collision must be 1.
<h3>What is momentum?</h3>
The term momentum is the product of mass and velocity. The principle of conservation of linear momentum states that total momentum before collision must be the same as the total momentum after collision thus the ratio of the total momentum after the collision to the total momentum before the collision must be 1.
Also, from the law of the conservation of energy; the ratio of the total kinetic energy after the collision to the total kinetic energy before the collision must be 1.
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Answer:
30 cm
Explanation:
f = Focal length = 25 cm
R = Radius of curvature (both sides are equal)
= Refractive index of lens = 1.6
The lens maker formula is given by
minus sign because it is on the other side
The radius of curvature of the glass surface is 30 cm
Answer:
a) dh/dt = -44.56*10⁻⁴ cm/s
b) dr/dt = -17.82*10⁻⁴ cm/s
Explanation:
Given:
Q = dV/dt = -35 cm³/s
R = 1.00 m
H = 2.50 m
if h = 125 cm
a) dh/dt = ?
b) dr/dt = ?
We know that
V = π*r²*h/3
and
tan ∅ = H/R = 2.5m / 1m = 2.5 ⇒ h/r = 2.5
⇒ h = (5/2)*r
⇒ r = (2/5)*h
If we apply
Q = dV/dt = -35 = d(π*r²*h/3)*dt
⇒ d(r²*h)/dt = 3*35/π = 105/π ⇒ d(r²*h)/dt = -105/π
a) if r = (2/5)*h
⇒ d(r²*h)/dt = d(((2/5)*h)²*h)/dt = (4/25)*d(h³)/dt = -105/π
⇒ (4/25)(3*h²)(dh/dt) = -105/π
⇒ dh/dt = -875/(4π*h²)
b) if h = (5/2)*r
Q = dV/dt = -35 = d(π*r²*h/3)*dt
⇒ d(r²*h)/dt = d(r²*(5/2)*r)/dt = (5/2)*d(r³)/dt = -105/π
⇒ (5/2)*(3*r²)(dr/dt) = -105/π
⇒ dr/dt = -14/(π*r²)
Now, using h = 125 cm
dh/dt = -875/(4π*h²) = -875/(4π*(125)²)
⇒ dh/dt = -44.56*10⁻⁴ cm/s
then
h = 125 cm ⇒ r = (2/5)*h = (2/5)*(125 cm)
⇒ r = 50 cm
⇒ dr/dt = -14/(π*r²) = - 14/(π*(50)²)
⇒ dr/dt = -17.82*10⁻⁴ cm/s
