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Tju [1.3M]
2 years ago
12

The length and width of a rectangle are shown below.

Mathematics
1 answer:
natulia [17]2 years ago
7 0

Answer:

-2x² + 90x + 500

Step-by-step explanation:

Use FOIL method

Area of rectangle = length * width

                             = (50 - x)(2x + 10)

                             = 50*(2x) + 50*10 + (-x)*2x + (-x)*10

                             = 100x + 500 - 2x² - 10x

                             = -2x² + 10<u>0x - 10x </u>+ 500  {Combine like terms}

                            = -2x² + 90x + 500

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in a random sample of 200 people, 154 said that they watched educational television. fine the 90% confidence interval of the tru
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Answer:

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<em>We can approximate this discrete binomial distribution with the continuous Normal distribution. As the sample size is large enough, not applying the continuity correction factor makes no significant  difference. </em>

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The 90% confidence interval for the proportion would be then  

\bf  [0.77-z^*0.0298, 0.77+z^*0.0298]

where \bf z^* is the 10% critical value for the Normal N(0,1) distribution , this is a value such that the area under the N(0,1) curve outside the interval \bf [-z^*,z^*] is 10%=0.1

We can either use a table, a calculator or a spreadsheet to get this value.

In Excel or OpenOffice Calc we use the function

<em>NORMSINV(0.95) and we get a value of 1.645 </em>

The 90% confidence interval for the proportion is then

\bf  [0.77-1.645^*0.0298, 0.77+1.645^*0.0298]=[0.7210,0.8189]

This means there is a 90% probability that the proportion of people who watch educational television is between 72.10% and 81.89%

If the television company wanted to publicize the proportion of viewers, do you think it should use the 90% confidence interval?

Yes, I do.

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