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Leona [35]
3 years ago
15

compute the mass-specific enthalpy change associated with Nz that is undergoing a change in state from 400 k to 800 k

Chemistry
1 answer:
Kitty [74]3 years ago
8 0

Answer:

The correct answer is "430 kJ/kg". A further explanation is given below.

Explanation:

The given values are:

T₁ = 400 k

T₂ = 800 k

The average temperature will be:

= \frac{T_1+T_2}{2}

= \frac{400+800}{2}

= 600 \ k

From table,

At 600 k the C p will be = 1.075

Now,

⇒ The specific enthalpy = Cp(T_2-T_1)

⇒                                \Delta h=1.075 (800-700)

⇒                                      =430 \ kJ/kg

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Krypton

Explanation:

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How much energy is needed to melt 47.6g of water
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15.9 kJ

Explanation:

Use the equation q = nΔH

q = (47.6)(334)

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or 15.9 kJ

5 0
3 years ago
When you finish using the compound brightfield microscope, what should you have your lab instructor do?
ira [324]

Answer:

To check if it's properly cleaned.

Explanation:

When you finish using a microscope, you have to take out all your samples you were using and make sure it is completely clean so that no further contamination affects future sample analysis.

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3 years ago
An ideal gas in a 1.25-gallon container is at a temperature of 125 degrees Celsius and pressure of 2.5 atmospheres. If the gas i
Tresset [83]
You will need the equation PV = nRT

P = Pressure in kPa
V = Volume in L
n = moles
R = 8.314 (constant)
T = Temperature in Kelvin 

First convert 2.5 atm into kPa:

2.5 X 101.3 = 253.25 kPa

Convert 125 Celsius into Kelvin:

125 + 273 = 398 K

Convert Gallons to Litres:

1.25  X 3.79 = 4.74 L

Plug your values into the equation to solve for n:

(253.25)(4.74) = n(8.314)(398)

n = (253.25)(4.74)/(8.314)(398)

n = 0.362 moles

Now use M = m/n to solve for the mass of O2

M = Molar Mass 
M = mass
n= moles

32 = m/(0.362)

m = (32)(0.362) 

m = 11.58g
8 0
3 years ago
Suppose 180 ml of 3.52x10^-4 M NaOH is mixed with 220 mL of 2.47x10^-4 M MgCl2.
velikii [3]
When in water, MgCl2 dissociates into magnesium ions and Cl- ions and NaOH into Na and OH ions. The equation is as follows:

MgCl2 = Mg2+ + 2Cl-
NaOH = Na+ + OH-

The initial concentrations are as follows:

[Mg2+] = .220(<span> 2.47x10^-4) / .220+.180 = 1.36x10^-4 M Mg2+
</span>[OH-] = .180 (3.52x10^-4) / .220+.180 = 1.58x10^-4 M OH-
6 0
3 years ago
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