Answer:
I’m pretty sure it’s Lions sleeping after a big meal
Explanation:
Answer:
Mass = 0.697 g
Explanation:
Given data:
Volume of hydrogen = 1.36 L
Mass of ammonia produced = ?
Temperature = standard = 273.15 K
Pressure = standard = 1 atm
Solution:
Chemical equation:
3H₂ + N₂ → 2NH₃
First of all we will calculate the number of moles of hydrogen:
PV = nRT
R = general gas constant = 0.0821 atm.L/mol.K
1atm ×1.36 L = n × 0.0821 atm.L/mol.K × 273.15 K
1.36 atm.L = n × 22.43 atm.L/mol
n = 1.36 atm.L / 22.43 atm.L/mol
n = 0.061 mol
Now we will compare the moles of hydrogen and ammonia:
H₂ : NH₃
3 : 2
0.061 : 2/3×0.061 = 0.041
Mass of ammonia:
Mass = number of moles × molar mass
Mass = 0.041 mol × 17 g/mol
Mass = 0.697 g
The correct answer to this question is "5." the oxidation number of cl in ClO3 will be a positive 5 because oxygen is naturally a -2 charge. times that by three and then account for the negative charge of the CLO3- ion.
Grams of oxygen are required to react with 13.0 grams of octane (C8H18) in the combustion of octane in gasoline is 45.5g
Octane is a hydrocarbon which burns in gasoline in presence of oxygen according to the given balanced chemical equation,
2C₈H₁₈ + 25O₂------> 16CO₂ + 18H₂0
Molar mass of octane = 114.23g/mol
Molar mass of Oxygen = 32g/mol
According to the stiochiometry of the balanced equation the mole ratio of Octane and Oxygen is 2:25
2 mole of octane needs 25 mole of oxygen
1 mole of octane needs 12.5 moleof oxygen
114.23g of octane needs 400g of oxygen
13g of octane needs 45.5g of oxygen
Mass of oxygen needed =45.5g
Hence, the Mass of oxygen needed is 45.5g for the combustion of octane in gasoline.
Learn more about Octane here, brainly.com/question/21268869
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Answer: The answer is C. The reaction system absorbs 22 kJ of energy from the surroundings.
Explanation: I just took the quiz and it said I got it right.
