The answer is B
As seen on the graph, the bus maintains a 9m/s speed for a majority of the trip to school.
The average acceleration between t = 5.6 s and t = 8.5 s is 2.31 m/s²
<h3>What is acceleration?</h3>
Acceleration is defined as the rate change of velocity with time.
acceleration a = (Δv) / (Δt)
An object is moving with initial velocity u =5.7 m/s and its final velocity v= -1.0 m/s.
Time taken for the change in speed, t= 8.5 - 5.6 = 2.9 seconds
The acceleration is given by
a = (-1 - 5.7)/ 2.9
a = - 2.31 m/s²
|a | = 2.31 m/s²
Thus, the object's acceleration is 2.31 m/s²
Learn more about acceleration.
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True I believe..................
What you do is, multiply 16.0 and 12.4 together. then multiply that by 40a
Part A:
For this part we’re assuming all the kinetic energy of the moving bumper car is converted into elastic potential energy in the spring since the car is brought to rest. Therefore you can find the total kinetic energy to get your answer:
KE = ½ mv^2
KE = ½ (200)(8)^2
KE = 6400 J
Part B:
Now you can use Hooke’s law to find the force:
F = kx
F = (5000)(0.2)
F = 1000 N
