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3 years ago

8

Why can someone please help me out

1 answer:

denis23 [38]3 years ago

4 0

D I think hope this helps

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How much energy is stored in the electric field of a 50-μm-diameter cell with a 7.0-nm-thick cell wall whose dielectric constant

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:<span> </span><span>Under the assumption that a cell is made up of two concentric spheres you find the surface are of the inside sphere which will be your A.

You already have your separation and dielectric constant so just use the formula you stated towards the end of your question and you get 8.93x10^-11 Farads which is about 89pF</span>

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3 years ago

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If a baseball is in space and someone hits it with a bat what does the ball do

Darina [25.2K]

Answer:

It's will fly like float

Explanation:

Since in space there is no gravity that everything can float

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3 years ago

Air bags are designed to deploy in 10 ms. Given that the air bags expand 20 cm as they deploy, estimate the acceleration of the

joja [24]

As it is given that the air bag deploy in time

$t = 10 ms = 0.010 s$

total distance moved by the front face of the bag

$d = 20 cm = 0.20 m$

Now we will use kinematics to find the acceleration

$d = v_i*t + \frac{1}{2}at^2$

$0.20 = 0 + \frac{1}{2}a*0.010^2$

$0.20 = 5 * 10^{-5}* a$

$a = 4000 m/s^2$

now as we know that

$g = 10 m/s^2$

so we have

$a = 400g$

so the acceleration is 400g for the front surface of balloon

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3 years ago

How many grams of sugar are in 0.5mol C6H12O6?

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Answer:

90.07794 grams

Explanation:

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2 years ago

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Suppose there are 100,000 signaling societies in our galaxy. What is the average distance between civilizations, assuming that c

Leokris [45]

Answer:

The average distance is 999.936 light years.

Solution:

As per the question:

Ours is the Milky Way Galaxy with the diameter:

D = 1,00,000 ly

Radius, R = $\frac{D}{2} = \frac{1,00,000}{2} = 50,000\ ly$

Now,

A = $\pi R^{2} = 50,000^{2}\pi = 7.8539\times 10^{9}\ ly^{2}$

The area to each civilization, A' is:

A' = $\frac{A}{10000} = \frac{7.8539\times 10^{9}}{10000} = 7.8539\times 10^{5}\ ly^{2}$

The radius of each area of civilization, r:

$A' = \pi r^{2}$

$r = \sqrt{\frac{A'}{\pi}}$

$r = \sqrt{\frac{7.8539\times 10^{5}}{\pi}} = 499.968\ ly$

Thus the average separation distance between civilizations is given as:

2r = $2\times 499.968 = 999.936\ ly$

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3 years ago