I=prt. Sub in what you know: 562.50=1500(r)(5). Multiply: 562.5=7500r. Divide to get the unknown by itself: .075=r or 10%=r. :)
Answer:
lateral area = 2320 m²
Step-by-step explanation:
The question wants us to calculate the lateral area of a square base pyramid. The square base pyramid has a side of 40 meters.The height is 21 meters.
Half of the square base is 40/2 = 20 meters . With the height it forms a right angle triangle. The hypotenuse side is the slant height of the pyramid.
Using Pythagoras's theorem
c² = a² + b²
c² = 20² + 21²
c² = 400 + 441
c² = 841
square root both sides
c = √841
c = 29 meters
The slant height of the pyramid is 29 meters.
The pyramid has four sided triangle. The lateral area is 4 multiply by the area of one triangle.
area of triangle = 1/2 × base × height
base = 40 meters
height = 29 meters
area = 1/2 × 40 × 29
area = 580
area of one triangle = 580 m²
Lateral area = 4(580)
lateral area = 2320 m²
Answer:
The second one, third one and the fifth one should be correct. (7 to the 18th power divided 7 to the 9th power, 7 to the 3rd power to the 3rd power, and 7 to the 4th power times 7 to the 5th power)
Step-by-step explanation:
7 to the 8th power times 7 equal 40353607 so if you do all the equations shown you can rule out which ones equal 40353607 and which ones don't. Have a nice sleep!
Answer:
Probability p( selecting 8 cities alphabetically) = 2.48×10^-5
Step-by-step explanation:
Number of possible ways of choosing 8 cities=Permutation P(n,k) = n!/(n-k)!
P(8,8)= 8!/(8-8)! = 8! = 40,320
Probability (selecting 8 cities alphabetically) = 1/40320 = 2.48×10^-5
Answer:
So then the best answer for this case would be:
C. 2.78
Step-by-step explanation:
For this case we have the following probabability distribution function given:
Score P(X)
A= 4.0 0.2
B= 3.0 0.5
C= 2.0 0.2
D= 1.0 0.08
F= 0.0 0.02
______________
Total 1.00
The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.
If we use the definition of expected value given by:
And if we replace the values that we have we got:
So then the best answer for this case would be:
C. 2.78