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Lana71 [14]
2 years ago
11

3/4 / 3/5 divided. write your answer in simplest form or as a mixed number in simplest

Mathematics
1 answer:
Gnoma [55]2 years ago
6 0

Answer: 5/4

Step-by-step explanation:

do the keep change flip method

then it will be 3/4*5/3 which then equals 15/12 after that you would divide by 3 cause it is the only number that would go in evenly then the answer will be 5/4 in the simplest form

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If the center of a circle is at (3,-6) and the diameter is 10 units, what is the equation for the circle
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Answer:(x-3)^2+(y+6)^2=25

Step-by-step explanation:

Center Of The circle is at (3,-6)

Diameter=10

Radius(r)=10/2

Radius(r)=5

a=3

b=-6

Equation of circle=(x-a)^2+(y-b)^2=r^2

Equation of circle=(x-3)^2+(y-(-6))^2=5^2

Equation of circle=(x-3)^2+(y+6)^2=25

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Step-by-step explanation:

Think about a clock. The hand of a clock goes clockwise. When you tighten something (righty tighty) you spin it clockwise. You can rotate an object, lets say a square, clockwise. You can also rotate it counterclockwise, in the other direction. Therefore, you can rotate an object clockwise and <u>counter</u>clockwise.

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How do you factor a polynomial when one root has been given
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7 0
3 years ago
Read 2 more answers
1. Two object accumulated a charge of
In-s [12.5K]

Answer:

The  magnitude of the electric force  between these two objects

will be: 181.274 N.

i.e.  F  =181.274 N

Step-by-step explanation:

As

Two object accumulated a charge of  4.5 μC and another a charge of 2.8  μC.

so

q₁ = 4.5 μC = 4.5 × 10⁻⁶ C

q₂ = 2.8  μC = 2.8 × 10⁻⁶  C

separated distance = d = 2.5 cm

Calculating the magnitude of the force between two charged objects using the formula:

F = \frac{1}{4\pi \epsilon_0}\frac{q_1 q_2}{r^2}

   =\:\frac{4.5\times \:\:10^{-6}\:\times \:\:2.8\:\times \:\:10^{-6}}{4\:\times \:\left(3.14\right)\:\times \:\left(8.85\times \:10^{-12}\right)\times \left(2.5\times \:\:10^{-2}\right)^2}

   =\frac{10^{-12}\times \:12.6}{10^{-12}\times \:4\times \:8.85\pi \left(10^{-2}\times \:2.5\right)^2}        ∵ 4.5\times \:10^{-6}\times \:2.8\times \:10^{-6}=10^{-12}\times \:12.6

   =\frac{10^{-12}\times \:12.6}{10^{-12}\times \:35.4\pi \left(10^{-2}\times \:2.5\right)^2}    ∵ \mathrm{Multiply\:the\:numbers:}\:4\times \:8.85=35.4

\mathrm{Cancel\:the\:common\:factor:}\:10^{-12}

  =\frac{12.6}{35.4\pi \left(10^{-2}\times \:2.5\right)^2}

  =\frac{12.6}{0.025^2\times \:35.4\pi }        ∵ \left(10^{-2}\times \:2.5\right)^2=0.025^2

  =\frac{12.6}{0.022125\pi }        ∵ 35.4\pi\times 0.025^2=0.022125\pi

   =\frac{12.6}{0.06950 }

F  =181.274 N

Therefore, the  magnitude of the electric force  between these two objects will be: 181.274 N.

i.e.  F  =181.274 N

7 0
3 years ago
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