In a neutral compound, the charges must balance, the net
charge should be zero.
Since the charge of Fe is 3+ and that of O is 2-, therefore,
there should be 2 Fe 3+ ions per 3 O2- ions in order to have a net charge of
zero.
Answer:
Lewis structure is shown in the image below.
Explanation:
Acetate ion (CH₃COO⁻)
Valence electrons of carbon = 4
Valence electrons of oxygen = 6
Valence electrons of hydrogen = 1
Charge = 1 (Negative which means that the electrons are being added)
The total number of the valence electrons = 2(4) + 2(6) + 3(1) + 1 = 24
The Lewis structure is drawn in such a way that the octet of each atom and duet for the hydrogen in the molecule is complete. So,
The Lewis structure is shown in the image below.
The given question is incomplete. The complete question is:
A chemist prepares a solution of barium chloride by measuring out 110 g of barium chloride into a 440 ml volumetric flask and filling the flask to the mark with water. Calculate the concentration in mole per liter of the chemist's barium chloride solution. Round your answer to 3 significant digits.
Answer: Concentration of the chemist's barium chloride solution is 1.20 mol/L
Explanation:
Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

where,
n = moles of solute
= volume of solution in L
moles of
(solute) = 
Now put all the given values in the formula of molality, we get

Therefore, the molarity of solution is 1.20 mol/L
A gaseous solute will <span> be able to be dissolve in a liter of liquid water by increasing the pressure of the gas. an example of this situation is the increase in solubility of carbon dioxide in sea water which turns it into an acidic environment for marines as pressure increases.</span>
Answer:

Explanation:
The concentration of CO2 in the room will be the amount of CO2 in the room at time t, divided by the volume of the room.
Let A(t) be the amount of CO2 in the room, in ft3 CO2.
The air entering the room is 3000 ft3/min with 0.06% concentrarion of CO2. That can be expressed as (3000*0.06/100)=1.8 ft3 CO2/min.
The mixture leaves at 3000 ft3/min but with concentration A(t)/V. We can express the amount of CO2 leaving the room at any time is A(t).
We can write this as a differential equation

We can rearrange and integrate

We also know that A(0) = 12000*(0.3/100)=36 ft3 CO2.

Then we have the amount A(t) as
