Answer:
The probability that another accident will occur that same month = 0.44907
Step-by-step explanation:
Let consider X to be the random variable that follows an exponential distribution with a mean of 52.
The mean of the exponential distribution
Thus, the probability distribution of X is:
Suppose X represents the time interval between the accident that happened in October 1 and the following accident.
Then, the probability that another accident will occur in the same month is the same as the event that the time between the two accidents are less than 31 (given that the month of October have 31 days)
Thus, we can calculate the required probability as follows:
Thus, the probability that another accident will occur that same month = 0.44907
38 Is it explain step by step
I think the answer is 3/5 if you simplify
Answer:
-1, 12 I believe
Step-by-step explanation:
find the distance between the two given plots and do the opposite to find your answer
Plane's air speed is 437.5 mph
Wind velocity is 87.5 mph
An actual question hasn't been asked, but an educated guess would be to determine the plane's airspeed or the wind velocity. So I'll calculate those values for you.
When traveling with the wind, the combined speed is 2100/4 = 525 mph.
When traveling against the wind, the combined speed is 2100/6 = 350 mph.
So we can create 2 equations with 2 unknowns. They are:
a - b = 350
a + b = 525
Let's add the two equations together.
a - b = 350
a + b = 525
2a = 875
a = 437.5
So the plane's speed in still air is 437.5 mph.
Let's calculate the wind velocity.
a + b = 525
437.5 + b = 525
b = 87.5
And the wind velocity is 87.5 mph