The list shows five processes that occur during digestion.

What happens to an atom of sulfur (S) if it loses an electron?

WITCHER [35]

Answer:

An atom becomes anion when it gains or loses electrons. The ions that are formed when an atom loses electrons are positively charged because they have more protons in the nucleus than electrons in the electron cloud.

Explanation:

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3 0

3 years ago

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How and why do ionic bonds form? Check all of the boxes that apply. Ionic bonds form between metal atoms and other metal atoms.

sammy [17]

2 Ionic bonds form between metal atoms and nonmetal atoms.

4 The less electronegative atoms transfers one or more electrons to the more electronegative atom.

5 The metal atom forms a cation and the nonmetal atom forms an anion.

7 The attraction between ions with an opposite charge forms an ionic bond.

8 0

3 years ago

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What is the electric force on a proton 2.5 fmfm from the surface of the nucleus? Hint: Treat the spherical nucleus as a point ch

sammy [17]

Explanation:

It is known that charge on xenon nucleus is $q_{1}$ equal to +54e. And, charge on the proton is $q_{2}$ equal to +e. So, radius of the nucleus is as follows.

r = $\frac{6.0}{2}$

= 3.0 fm

Let us assume that nucleus is a point charge. Hence, the distance between proton and nucleus will be as follows.

d = r + 2.5

= (3.0 + 2.5) fm

= 5.5 fm

= $5.5 \times 10^{-15} m$ (as 1 fm = $10^{-15}$ )

Therefore, electrostatic repulsive force on proton is calculated as follows.

F = $\frac{1}{4 \pi \epsilon_{o}} \frac{q_{1}q_{2}}{d^{2}}$

Putting the given values into the above formula as follows.

F = $\frac{1}{4 \pi \epsilon_{o}} \frac{q_{1}q_{2}}{d^{2}}$

= $(9 \times 10^{9}) \frac{54e \times e}{(5.5 \times 10^{-15})^{2}}$

= $(9 \times 10^{9}) \frac{54 \times (1.6 \times 10^{-19})^{2}}{(5.5 \times 10^{-15})^{2}}$

= 411.2 N

or, = $4.1 \times 10^{2}$ N

Thus, we ca conclude that $4.1 \times 10^{2}$ N is the electric force on a proton 2.5 fm from the surface of the nucleus.

8 0

4 years ago

Suppose a 1.0 L solution contains 0.020 M in Cu(NO3)2, then 0.40 moles of NH3 are added. Assuming no change in volume, what is t

Rasek [7]

Answer:

$4.6*10^{-14}$ M

Explanation:

Concentration of $Cu^{2+} = [Cu(NO_3)_2]$ = 0.020 M

Constructing an ICE table;we have:

$Cu^{2+}+4NH_3_{aq} \rightleftharpoons [Cu(NH_3)_4]^{2+}_{(aq)}$

Initial (M) 0.020 0.40 0

Change (M) - x - 4 x x

Equilibrium (M) 0.020 -x 0.40 - 4 x x

Given that: $K_f =1.7*10^{13}$

$K_f } = \frac{[Cu(NH_3)_4]^{2+}}{[Cu^{2+}][NH_3]^4}$

$1.7*10^{13} = \frac{x}{(0.020-x)(0.40-4x)^4}$

Since x is so small; 0.40 -4x = 0.40

Then:

$1.7*10^{13} = \frac{x}{(0.020-x)(0.0256)}$

$1.7*10^{13} = \frac{x}{(5.12*10^{-4}-0.0256x)}$

$1.7*10^{13}(5.12*10^{-4} - 0.0256x) = x$

$8.704*10^9-4.352*10^{11}x =x$

$8.704*10^9 = 4.352*10^{11}x$

$x = \frac{8.704*10^9}{4.352*10^{11}}$

$x = 0.0199999999999540$

$Cu^{2+}= 0.020 - 0.019999999999954$

$Cu^{2+} = 4.6*10^{-14}$ M

8 0

3 years ago

Uses of baking powder

NARA [144]

Baking powder is used to increase the volume and lighten the texture of baked goods. It works by releasing carbon dioxide gas into a batter or dough through an acid–base reaction, causing bubbles in the wet mixture to expand and thus leavening the mixture.

7 0

3 years ago

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