Can someone help me on this?
1 answer:
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The radius of the circle is given to be r = 14.5
Let the center be O. So OB is the radius = 14.5
We can draw a triangle as shown in the image below. We have a right angled triangle. We know the hypotenuse and the base, we need to find the perpendicular side. This can be done using the Pythagorean theorem.
So, we can write:
Thus, the measure of OA = 10.5
OB = OA + AB
14.5 = 10.5 + AB
⇒
AB = 4
Let the center be O. So OB is the radius = 14.5
We can draw a triangle as shown in the image below. We have a right angled triangle. We know the hypotenuse and the base, we need to find the perpendicular side. This can be done using the Pythagorean theorem.
So, we can write:
Thus, the measure of OA = 10.5
OB = OA + AB
14.5 = 10.5 + AB
⇒
AB = 4
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<h3>I'm solving it using substitution method:-</h3><h3>7x+2y=3 {given}</h3><h3>=>7x=3-2y</h3><h3>=>x=(3-2y)/7-------(1)</h3><h3>x-3y=30 {given}</h3><h3>=>x=30+3y</h3><h3>=>(3-2y)/7=30+3y {putting the value of x from eqn 1}</h3><h3>=>3-2y=210+21y</h3><h3>=>3-210=21y+2y</h3><h3>=>-207=23y</h3><h3>=>y= -207/23= -9</h3><h3>putting the value of y on eqn(1):-</h3><h3>x=(3-2y)/7</h3><h3>x=>(3-2(-9))/7=(3+18)/7=21/7=3</h3><h2>Hence, x=3, y= -9</h2>✌️✌️❤️❤️
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