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3 years ago

13

We know that the frequency and wavelength of an oscillation are related by the velocity of the wave . In standing waves, the wav

e velocities of the different harmonics are the same.Think about why this may be and explain that in your notebook. (Hint: The wave velocity is dependent on the static properties of the oscillating object like mass per unit length and tension)

1 answer:

Sidana [21]3 years ago

3 0

Answer

the medium does not change the speed of the on they should change.

Explanation:

The speed of the waves is constant for a given medium, depending on the physical properties of the medium,

When a wave is strapped on a wall of a medium it does not change the properties of the medium, the wave changes direction, but since the medium does not change the speed of the on they should change.

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Digestion and Absorbtion

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A long hollow cylindrical conductor (inner radius = 2.0 mm, outer radius = 4.0 mm) carries a current of 12 a distributed uniform

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Here we can use ampere'a law to find the magnetic field

$\int B.dl = \mu_o i_{en}$

$B*2 \pi r = \mu_o (i_1 + \frac{i_2*\pi(3^2 - 2^2)}{\pi(4^2 - 2^2}$

$B*2 \pi*0.003 = 4\pi * 10^{-7} (12 + 5)$

$B = 4\pi * 10^{-7} (12 + 5)$

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3 years ago

point) A tank in the shape of an inverted right circular cone has height 5 meters and radius 4 meters. It is filled with 4 meter

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Answer:

W = 907963.50 J = 907.96 J

Explanation:

Note: Refer to the figure attached

Now, from the figure we have similar triangles ΔAOB and ΔCOD

we have

$\frac{5}{4}=\frac{x}{r}$

or

$r=\frac{4x}{5}$

Now, the work done to empty the tank can be given as:

$W = \int\limits^4_0 {(5-x)\rho\times g A} \, dx$

or

$W = \int\limits^4_0 {(5-x)1080\times 9.8 (\pi r^2)} \, dx$

or

$W = \int\limits^4_0 {(5-x)\times10584\times (\pi (\frac{4x}{5})^2)} \, dx$

or

$W = 6773.76\pi\int\limits^4_0 {(5-x)x^2)} \, dx$

or

$W = 6773.76\pi[\frac{5}{3}x^3-\frac{1}{4}x^4]^4_0$

or

$W = 6773.76\pi[\frac{128}{3}]$

or

W = 907963.50 J = 907.96 J

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3 years ago

An ideal gas is contained in a vessel at 300 K. The temperature of the gas is then increased to 900 K. (i) By what factor does t

Dahasolnce [82]

The question is missing some parts. Here is the complete question.

An ideal gas is contained in a vessel at 300K. The temperature of the gas is then increased to 900K.

(i) By what factor does the average kinetic energy of the molecules change, (a) a factor of 9, (b) a factor of 3, (c) a factor of $\sqrt{3}$ , (d) a factor of 1, or (e) a factor of $\frac{1}{3}$ ?

Using the same choices in part (i), by what factor does each of the following change: (ii) the rms molecular speed of the molecules, (iii) the average momentum change that one molecule undergoes in a colision with one particular wall, (iv) the rate of collisions of molecules with walls, and (v) the pressure of the gas.

Answer: (i) (b) a factor of 3;

(ii) (c) a factor of $\sqrt{3}$ ;

(iii) (c) a factor of $\sqrt{3}$ ;

(iv) (c) a factor of $\sqrt{3}$ ;

(v) (e) a factor of 3;

Explanation: (i) Kinetic energy for ideal gas is calculated as:

$KE=\frac{3}{2}nRT$

where

n is mols

R is constant of gas

T is temperature in Kelvin

As you can see, kinetic energy and temperature are directly proportional: when tem perature increases, so does energy.

So, as temperature of an ideal gas increased 3 times, kinetic energy will increase 3 times.

For temperature and energy, the factor of change is 3.

(ii) Rms is root mean square velocity and is defined as

$V_{rms}=\sqrt{\frac{3k_{B}T}{m} }$

Calculating velocity for each temperature:

For 300K:

$V_{rms1}=\sqrt{\frac{3k_{B}300}{m} }$

$V_{rms1}=30\sqrt{\frac{k_{B}}{m} }$

For 900K:

$V_{rms2}=\sqrt{\frac{3k_{B}900}{m} }$

$V_{rms2}=30\sqrt{3}\sqrt{\frac{k_{B}}{m} }$

Comparing both veolcities:

$\frac{V_{rms2}}{V_{rms1}}= (30\sqrt{3}\sqrt{\frac{k_{B}}{m} }) .\frac{1}{30} \sqrt{\frac{m}{k_{B}} }$

$\frac{V_{rms2}}{V_{rms1}}=\sqrt{3}$

For rms, factor of change is $\sqrt{3}$

(iii) Average momentum change of molecule depends upon velocity:

q = m.v

Since velocity has a factor of $\sqrt{3}$ and velocity and momentum are proportional, average momentum change increase by a factor of

(iv) Collisions increase with increase in velocity, which increases with increase of temperature. So, rate of collisions also increase by a factor of $\sqrt{3}$ .

(v) According to the Pressure-Temperature Law, also known as Gay-Lussac's Law, when the volume of an ideal gas is kept constant, pressure and temperature are directly proportional. So, when temperature increases by a factor of 3, Pressure also increases by a factor of 3.

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3 years ago

Which of the following is responsible for the formation of sinkholes F. Eroding soil on Earths’s surface G. Ice that builds up o

monitta

Ans is <span>I. Flowing groundwater that dissolves rock , such as limestone</span>

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3 years ago