Answer:
3.258 m/s
Explanation:
k = Spring constant = 263 N/m (Assumed, as it is not given)
x = Displacement of spring = 0.7 m (Assumed, as it is not given)
= Coefficient of friction = 0.4
Energy stored in spring is given by
As the energy in the system is conserved we have
The speed of the 8 kg block just before collision is 3.258 m/s
Answer:
165.2762 m/sec
Explanation:
The initial mass of the rocket and the fuel
M₀ = 5.02e6 kg
The initial mass of the fuel
Mf₀ = 1.25e6 kg
The rate of fuel consumption
dm/dt = 370 kg/sec
The duration of the rocket burn
Δt = 450 sec
The rocket exhaust speed
Ve = 4900 m/sec
The thrust, T
T = Ve (dm/dt) = 1813000 kg m/sec²
The mass of the expended propellant, ΔM
ΔM = Δt (dm/dt) = 166500 kg
The rocket's mass after the burn
M₁ = M₀ − ΔM = 4853500 kg
The speed of the rocket after the burn
Δv = Ve ln(M₀/M₁) = 165.2762 m/sec
It has holes (an electron deficiency).
The Earth's radius is 6371 km. So that's our distance from the center when we're on the surface.
The Shuttle astronaut's distance from the center, when s/he's in orbit, is 330 km greater ... that's 6701 km.
The force of gravity is inversely proportional to the distance between the center of the Earth and the center of the astronaut. So, in orbit, it's
(6371/6701)^2 = 90.4 %
of its value on the surface.
