Answer:
v = 2.45 m/s
Explanation:
first we find the time taken during this motion by considering the vertical motion only and applying second equation of motion:
h = Vi t + (1/2)gt²
where,
h = height of cliff = 15 m
Vi = Initial Vertical Velocity = 0 m/s
t = time taken = ?
g = 9.8 m/s²
Therefore,
15 m = (0 m/s) t + (1/2)(9.8 m/s²)t²
t² = (15 m)/(4.9 m/s²)
t = √3.06 s²
t = 1.75 s
Now, we consider the horizontal motion. Since, we neglect air friction effects. Therefore, the horizontal motion has uniform velocity. Therefore,
s = vt
where,
s = horizontal distance covered = 4.3 m
v = original horizontal velocity = ?
Therefore,
4.3 m = v(1.75 s)
v = 4.3 m/1.75 s
<u>v = 2.45 m/s</u>
Definitely ball and basket
The mass of the astronaut is still 65 kilograms. Mass is constant or doesn't change no matter where you are.
FOLLOW ME FOR CLEARING YOUR NEXT DOUBT
Answer:
w = 706.32 [N]
Explanation:
The force due to gravitational acceleration can be calculated by means of the product of mass by gravitational acceleration.
w = m*g
where:
w = weight [N] (units of Newtons)
m = mass = 72 [kg]
g = gravity acceleration = 9.81 [m/s²]
Then we have:
![w = 72*9.81\\w = 706.32 [N]](https://tex.z-dn.net/?f=w%20%3D%2072%2A9.81%5C%5Cw%20%3D%20706.32%20%5BN%5D)